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FromTheMoon [43]
3 years ago
7

If a line with a slope of 4 crosses the y-axis at (0, 1), what is the equation of the line? y − 4x = 1 y + 4x = 1 x − 4y = 1 x +

4y = 1
Mathematics
1 answer:
levacccp [35]3 years ago
5 0
The answer is y - 4x = 1
the simplest thing to do is make it into y = mx + b 
this equation will become y = 4x + 1 
and when you graph it the y axis will 1 or (0,1)
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What is the value of x?<br> X<br> 60°<br> 14
djverab [1.8K]

Answer:

7

Step-by-step explanation:

Given that the two angles are 90 and 60, we can find out that the missing angle is 30 degrees.

According to leg opposite to 30 degree angle (which states that the leg opposite to the 30 degree angle is half the hypotenuse), x is equal to 14/2 or 7.

Hope this helps :)

Have a great day!

7 0
2 years ago
Which of the following is a solution to the system shown below? y = 3x 2 - 8x - 2 and 2x - y = 5
wolverine [178]
A graph shows the solutions to be
.. (1/3, -4 1/3)
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7 0
4 years ago
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Need help with 73, 74, 75, &amp; 76. Find the value of X.
bija089 [108]

Answer:

see explanation

Step-by-step explanation:

73.

18 = 3x\sqrt{3} (divide both sides by 3 )

6 = x\sqrt{3} ( multiply both sides by \sqrt{3} )

6\sqrt{3} = 3x [ \sqrt{3} × \sqrt{3} = 3 ]

divide both sides by 3

x = 2\sqrt{3}

74.

24 = 2x\sqrt{2} ( divide both sides by 2 )

12 = x\sqrt{2} ( multiply both sides by \sqrt{2} )

12\sqrt{2} = 2x ( divide both sides by 2 )

x = 6\sqrt{2}

75.

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x = 2

76.

2 = x × \frac{4}{\sqrt{3} } ( multiply both sides by \sqrt{3} )

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8 0
3 years ago
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PLEASE ANSWERRRRRRRRRRRRRR
Gelneren [198K]

Answer:

A. y = \frac{1}{2}x + 10

Step-by-step explanation:

Given;

  • The equation y = -7x - 5
  • and another equation have a solution of (-2, 9)

If we equate the value of y in the first equation and the value of y in the second equation, then the solution of x should be -2 . Let's test this with equation A:

-7x - 5 = \frac{1}{2}x + 10

-7x - \frac{1}{2}x = 10 + 5

-\frac{15}{2}x = 15

x = (15 × -2) ÷ 15 = -2

*<em>This proves that equation A has the same value of x as our first equation!</em>

<em />

Let's test if equation A has a solution; y = 9:

y = \frac{1}{2}(-2) + 10 = 9

*<em>This proves that equation A has the same value of y as our first equation!</em>

<em />

So the second equation is,

A. y = \frac{1}{2}x + 10

<em />

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3 years ago
Find all the zeroes of the equation 2x^4-5x^3+53x^2-125x+75=0
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3 years ago
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