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alina1380 [7]
3 years ago
5

Which of the following is a solution to the system shown below? y = 3x 2 - 8x - 2 and 2x - y = 5

Mathematics
2 answers:
wolverine [178]3 years ago
7 0
A graph shows the solutions to be
.. (1/3, -4 1/3)
.. (3, 1)

o-na [289]3 years ago
6 0

Answer:

(1/3, -13/3)

Step-by-step explanation:

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Peyton has collected 120 aluminum cans for recycling. If 20 cans will fit in each blue plastic bag, how many bags will she need
gogolik [260]

Hi Renee!

--------------------------------------------

We Know:

120 aluminum cans.

20 cans fit in each blue bag.

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Solution:

120 / 20 = 6

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Answer:

She will need 6 bags to carry all the aluminum cans.

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Hope This Helps :)

6 0
2 years ago
Exercise #4
vlada-n [284]

Answer: im not smart so i cant anwer that

Step-by-step explanation:

:)

7 0
3 years ago
Which equation represents a line that passes through (2, –1/2) and has a slope of 3?
KIM [24]
Hello,

y+1/2=3(x-2)
or y=3x-13/2

8 0
3 years ago
Read 2 more answers
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
Help please algebra
Murljashka [212]

The answer is D. -24 - 49i/13

4 0
3 years ago
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