What are the key steps required for an individual to vote (govt class)

Advanced Placement (AP)

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer: have legal citizenship

Explanation:

You might be interested in

How are you Seabass?

Lilit [14]

What do you mean? Do you mean an animal?

4 0

3 years ago

PLEASE HELP!!! I’LL MARK BRAINIEST! ITS FOR PSYCHOLOGY!!!

Stels [109]

The answer is c psycho

4 0

3 years ago

Why was industrialization concentrated in the northern United States until the mid-twentieth century? The South lacked infrastru

ser-zykov [4K]

Answer: The South lacked infrastructure.

Explanation:

The Northern part of the United States was much more industrialized than the South and this contributed in no small part to the Union victory during the Civil War.

The major reason for this was the extensive infrastructure that had been built in Northern states such as Railroad network and the ship building industries of New England. With such infrastructure providing access to markets, more industries were set up in the North to take advantage of this accessibility.

8 0

3 years ago

If the wait time is less than 30 minutes for 75% of all patients in the emergency room, what is the probability that the

Greeley [361]

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less is 0.0020

<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

The sample size (n) = 55 patients
Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion $\mathbf{\hat p}$ can be computed by using the expression:

$\mathbf{\hat p = \dfrac{x}{n}}$

$\mathbf{\hat p = \dfrac{32}{55}}$

$\mathbf{\hat p =0.582}$

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

$\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}$