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vazorg [7]
3 years ago
8

Give me explain Associative property of addition??

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0
Associative property of addition states: a + (b + c) = (a + b) + c



Don't get confused with the commutative property which states: a + b = b + a
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Distributive property of 16x + 24
mina [271]

Answer:

8(2x+3)

Step-by-step explanation:

Find the GCF (greatest common factor) of 16 and 24

The GCF is 8

divide both by eight

there you go....

I'm not good at explaining this ;-; ,my sincere apologies.

Hopefully I was helpful!

4 0
3 years ago
What is the prime factorozation of 760 in expended form
harina [27]
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Because those are the prime number factors of 760
8 0
3 years ago
Solve quadratic equations by factoring<br> x cubed +3x squared - 4x= 0
Papessa [141]
<span>x cubed +3x squared - 4x= 0
= x^3 + 3x^2 -4x = 0
=x(x^2 +3x -4) = 0
= x (x+4)(x-1) = 0

x = 0
x+ 4 = 0 then x = -4
x - 1 = 0 then x = 1
answer: x = 0, x = -4 and x = 1</span>
8 0
3 years ago
Read 2 more answers
What is the radius of a circular lid with a diameter of 5 centimeters?<br> radius
Alja [10]

Answer:

5/2 =

<u>2.5</u>

Step-by-step explanation:

6 0
3 years ago
Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe
AlekseyPX
The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
\frac{\sqrt{-9}}{(4-7i)-(6-6i)}&#10;\\&#10;\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}&#10;\\&#10;\\=\frac{3i}{-2-i}

To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}&#10;\\&#10;\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}&#10;\\&#10;\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}&#10;\\&#10;\\=\frac{-6i+3i^2}{4-2i+2i-i^2}&#10;\\&#10;\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
7 0
3 years ago
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