Question

What is the sine of angle x ?

Answer 1

Answer:  $sinx=\frac{b}{c}$

Step-by-step explanation:

By definition you have that:

$sin\alpha=\frac{opposite}{hypotenuse}$

Based on the figure attached in the problem you have that:

$\alpha=x\\opposite=b\\hypotenuse=c$

Therefore, you must substitute the above into $sin\alpha=\frac{opposite}{hypotenuse}$

Then, the answer is:

$sinx=\frac{b}{c}$

Answer 2

Hello!

The answer is: $sin(x)=\frac{b}{c}$

Why?

Since it's a right triangle, we can determine the Sine of the angle "x" using the following formula:

$sin(x)=\frac{b}{c}$

Where:

$b=opposite\\a=hypotenuse$

Also, we can determine the cosine and the tangent of the same angle "x" using the following formulas:

$cos(x)=\frac{a}{c} \\tan(x)=\frac{b}{a}$

Where:

$a=hypotenuse\\b=opposite\\c=adjacent$

Have a nice day!