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dedylja [7]
3 years ago
11

What is the product of (x-2)(x-6)? *

Mathematics
2 answers:
belka [17]3 years ago
7 0

Answer:

x^2-4x+12

Step-by-step explanation:

(x-2)(x-6)

x(x-6)-2(x-6)

x^2-6x-2x+12

x^2-4x+12

Softa [21]3 years ago
4 0
<h3>hope it helped :-)</h3><h3>thank you</h3>

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Please help me! I will give you Brainlist if you get it right!​
tatuchka [14]

Answer:

B

Step-by-step explanation:

Find the area of the circle with r = 36/2     Area1 =  π r²

divide Area1 by two since the upper part of the figure is a semi-circle

then finally add and area of the rectangle   Area2 = (18)(36)

Total area = Area 1 + Area 2

5 0
2 years ago
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What is the GCF of 54 and 32?
Musya8 [376]
3
32: 2 2 2 2 2
GCF: 2
8 0
3 years ago
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Simplify the following expression: -7(3e-2f+4)+6e-2
tankabanditka [31]

Answer:

-15e+14f-30

Step-by-step explanation:

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-15e+14f-30

3 0
3 years ago
Trina has a total of 32 crayons.how many boxes of crayons did she buy
Sever21 [200]
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4 0
3 years ago
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A line segment has endpoints A(4, 8) and B(2, 10). The point M is the midpoint of AB. What is an equation of a line perpendicula
Vera_Pavlovna [14]
I)

The Midpoint M of the line segment AB is found using the Midpoint formula:

M=( \frac{4+2}{2} , \frac{8+10}{2})=(3, 9)

ii)

the slope of the line through A and B is found by the slope formula:

m= \frac{y_1-y_2}{x_2-x_1}= \frac{10-8}{2-4}= \frac{2}{-2}=-1

iii)

the product of the slopes of 2 perpendicular lines is -1, so the slope of the line perpendicular to the line through A and B is -1/(-1)=1

iv) 

the equation of the line with slope 1, which contains point M(3, 9) is found by the slope point form equation of a line:

y-9=1(x-3)

y-9=x-3

y=x+6


Answer: y=x+6

7 0
3 years ago
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