Which of the following functions is graphed below?

Which pair of numbers has a product of -24 and a sum of 10?

muminat

Answer:

-2;12

Step-by-step explanation:

it's too easy!

6 0

3 years ago

Read 2 more answers

Solve for X, will give you brainliest and a like

grigory [225]

Answer

Step-by-step explanation:

One solution :

x = -1/3 = -0.333

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

-5*(3*x+1)+4*x-(10*x+2)=0

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((0 - 5 • (3x + 1)) + 4x) - (10x + 2) = 0

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

-21x - 7 = -7 • (3x + 1)

Equation at the end of step 3 :

-7 • (3x + 1) = 0

Step 4 :

Equations which are never true :

4.1 Solve : -7 = 0

4 0

3 years ago

Read 2 more answers

Determine whether each given value of x satisfies the inequality x+1<x/3

Vinil7 [7]

$x+1 < \dfrac{x}{3}\ \ \ \ |\cdot3\\\\3x+3 < x\ \ \ \ |-3\\\\3x < x-3\ \ \ \ |-x\\\\2x < -3\ \ \ \ |:2\\\\x < -1.5$

Answer: (c) x = -4

5 0

3 years ago

The width of a rectangle is the length minus 7 units. The area of the

AleksandrR [38]

Answer:

8 units

Step-by-step explanation:

here's your solution

=> let the length of rectangle be X

=> then width = x - 7

=> area = 8units

=>> area = length*width

=> area = x (x-7) = 8

=> x^2 - 7 = 8

=> now, x^2 - 7x - 8 = 0

=> factories the above equation by middle term split

=> x^2 - 7x - 8

=> x^2 - 8x + x - 8

=> take the common

=> x(x - 8) + 1(x - 8)

=> (x + 1) (x - 8)

neglect (x + 1) because this will in negative for X

=> x - 8 = 0

=> x = 8

=>so, x = 8

=>length = 8 units

3 0

2 years ago

PLZ help me fast 2 mins left

jek_recluse [69]

Answer:

$\sqrt{-5}=i\sqrt{5}$

$\sqrt{-25}=5i$

Step-by-step explanation:

i is an imaginary unit, this means

$i^2=-1$

Rewrite -5 as $5\cdot (-1)=5\cdot i^2,$

then

$\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}$

Rewrite -25 as $-25=25\cdot (-1)=25\cdot i^2,$

then

$\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i$

6 0

3 years ago