Question

B) In the given figure, If AB = AC and < ABC = 65°, Find the value of

Answer 1

Answer:

<ACB = $65^{o}$ and <BAC = $50^{o}$

Step-by-step explanation:

The given triangle is an isosceles triangle. Thus its two sides are equal and base angles are equal.

So that;

<ACB = <ABC

<ACB = $65^{o}$ (property of an isosceles triangle)

Then,

<ABC + <ACB + <BAC = $180^{o}$

$65^{o}$ + $65^{o}$ + <BAC = $180^{o}$

130 + <BAC = $180^{o}$

<BAC = $180^{o}$ - $130^{o}$

          = $50^{o}$

<BAC = $50^{o}$

Thus, <ACB = $65^{o}$ and <BAC = $50^{o}$.