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2 years ago

In the figure below, PR and PQ are tangent to the circle with center O. Given that OQ = 10 and OP = 26, find PR.

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

6 0

<h3>Answer: PR = 24</h3>

Explanation:

OQ = 10 is the radius, and so is segment RO. Both are the same length as they are the radii of the same circle. Triangle ORP has a leg of RO = 10 and a hypotenuse of PO = 26. The unknown side is PR = x.

Use the pythagorean theorem. We can use this theorem because the tangent formed (at point R) creates a 90 degree angle.

a^2 + b^2 = c^2

(PR)^2 + (RO)^2 = (PO)^2

x^2 + 10^2 = 26^2

x^2 + 100 = 676

x^2 = 676 - 100

x^2 = 576

x = sqrt(576) ... apply square root

x = 24

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Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

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Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

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1 year ago

The diameter of a circle is 6 inches. What is the circle's circumference?

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Answer:

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2 years ago

When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has incr

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Answer:

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m = 2

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2 years ago

Read 2 more answers

In the figure below, PR and PQ are tangent to the circle with center O. Given that OQ = 10 and OP = 26, find PR.​

In the figure below, PR and PQ are tangent to the circle with center O. Given that OQ = 10 and OP = 26, find PR.