Answer:
heterozygous (Aa) are 0.085 = or 8.54%
Step-by-step explanation:
The heterozygous individuals are carriers of the sickle cell trait. They have a genotype of Aa and are represented by the 2pq term
in the H-W equilibrium equations.
According to the question 0.2% of the population is affected with sickle cell anemia, thus q^2
= 0.2% = 0.002 in decimal. So, q =
sqr(q^2)
or sqr(0.002) =
0.04472
and p + q = 1, thus p = 1 – q = 1 – 0.04472 = 0.96
Thus, A allele has a frequency of 0.96 and the a allele has a frequency of 0.04472. Therefore, the
percentage of the population that is heterozygous (Aa) and are carriers is = 2pq = 2× 0.04472× 0.96 =0.085 = or 8.54%
The answer is just 60 I think
Answer:
639.341 lbs
Step-by-step explanation:
1 kilogram is approximately 2.2lbs
Answer:
$201,600
Step-by-step explanation:
Multiply 34 and 84, which is 2016. Then add 2 zeros at the end because there are 2 zeros in 8400. So, the answer is 201,600 dollars.
The correct simplification will be: (b) ab²
Here we will use the property of exponents for division of two exponential terms with same bases. The original property is : 
It means if the bases are same , then we will just subtract the exponents while dividing two terms.
Using this property:
and 
So, 
