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anyanavicka [17]
3 years ago
10

Avery selects chips from a bag without looking at them. The bag has 5 green chips, 3 red chips, and 7 blue chips. What is the pr

obability that he selects a red or blue chip? A. 1/3
B. 7/15
C. 2/3
D. 14/15
Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0
2/3 is your answer. Have a nice day
kumpel [21]3 years ago
4 0

Answer:

C. 2/3

Step-by-step explanation:

p(event) = (number of desired outcomes)/(total number of outcomes)

The total number of outcomes is the sum of the numbers of all chips.

5 + 3 + 7 = 15

The desired outcomes are any red or blue chips to be drawn.

There are 3 red chips and 7 blue chips.

3 + 7 = 10

Number of desired outcomes = 10

p(red or blue) = 10/15 = 2/3

Answer: C. 2/3

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Crazy boy [7]

Answer:

106

Step-by-step explanation:

Sum of angles around a point = 360 degrees

Sum of given angles = 164+90 = 254

Thus, the value of x is the angles remaining from 254 to make 360

360-254 = 106

Hope this helps

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A heptagon is a polygon.

It has 7 sides

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Measurements of regular hexagon
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The regular hexagon has both reflection symmetry and rotation symmetry.

Reflection symmetry is present when a figure has one or more lines of symmetry. A regular hexagon has 6 lines of symmetry. It has a 6-fold rotation axis.

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5 0
3 years ago
Simplify completely x^2+4x-45 / x^2+10x+9
S_A_V [24]

Answer: x - 5/x + 1

Step-by-step explanation:

This algebraic fraction

The task to be performed here is factorisation and simplification. Now going by the question,

x² + 4x - 45/x² + 10x + 9, the factorisation of

x² + 4x - 45 = x² + 9x - 5x - 45

= x(x + 9 ) - 5(x + 9 )

= ( x + 9 )(x - 5 ), don't forget this is the algebraic fraction's Numerator

The second part

x² + 10x + 9 = x² + x + 9x + 9

= x(x + 1) + 9( x + 1 )

= ( x + 9 )( x + 1 ), this is the algebraic denominator.

Now place the second expression which is the denominator under the first expression which is the numerator.

( x + 9 )( x - 5 )/( x + 9 )( x + 1 ).

You can see that, ( x + 9 )/( x + 9 ) divide each other , therefore therr then cancelled and left with

x - 5/x + 1

4 0
4 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
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