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anyanavicka [17]
3 years ago
10

Avery selects chips from a bag without looking at them. The bag has 5 green chips, 3 red chips, and 7 blue chips. What is the pr

obability that he selects a red or blue chip? A. 1/3
B. 7/15
C. 2/3
D. 14/15
Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0
2/3 is your answer. Have a nice day
kumpel [21]3 years ago
4 0

Answer:

C. 2/3

Step-by-step explanation:

p(event) = (number of desired outcomes)/(total number of outcomes)

The total number of outcomes is the sum of the numbers of all chips.

5 + 3 + 7 = 15

The desired outcomes are any red or blue chips to be drawn.

There are 3 red chips and 7 blue chips.

3 + 7 = 10

Number of desired outcomes = 10

p(red or blue) = 10/15 = 2/3

Answer: C. 2/3

You might be interested in
Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

cot x = \frac{cos x}{sin x}

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

4 0
4 years ago
What is the value of the underlined digit 1,711,799.
Varvara68 [4.7K]
I don't know which one is underlined so I will write it out in words.
One million seven hundred and eleven thousand and seven hundred ninety-nine.

Hope I helped :)

 
3 0
3 years ago
Will give brainliest if u help
WARRIOR [948]

Answer:

1. the translation from the original to the translated figure was 2 units up and 1 unit to the left

2. the points of the translated figure if it were translated 2 units down and 3 units to the right would be: A' (4,0), B' (6,-6), C' (5,3), D' (-1,0)

Step-by-step explanation:

8 0
3 years ago
A company introduces a new product for which the number of units sold S is
KonstantinChe [14]
(a) The "average value" of a function over an interval [a,b] is defined to be 

(1/(b-a)) times the integral of f from the limits x= a to x = b. 

Now S = 200(5 - 9/(2+t)) 

The average value of S during the first year (from t = 0 months to t = 12 months) is then: 

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12 

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12 

This equals 200/12 * (5t -9ln(2+t)) 

Evaluating this with the limits t= 0 to t = 12 gives: 

708.113 units., which is the average value of S(t) during the first year. 


(b). We need to find S'(t), and then equate this with the average value. 

Now S'(t) = 1800/(t+2)^2 

So you're left with solving 1800/(t+2)^2 = 708.113 

<span>I'll leave that to you</span>
6 0
3 years ago
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
4 years ago
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