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loris [4]
2 years ago
7

Help ASAP.. PLZ

Mathematics
1 answer:
wel2 years ago
3 0

a .right and absolute value function family

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Mario's company makes unusually shaped imitation gemstones. One gemstone had 10 faces and 12 vertices. How many edges did the ge
igor_vitrenko [27]
I think 20 but not sure (:
5 0
3 years ago
take a hiset math test need help refresh with my study guide.and refresh help calculator how to use a scientific one​
n200080 [17]

Answer:

B) 4,320

Step-by-step explanation:

You would first find the volume of the triangular prism using this formula:

V = 1/2 x A x C x H

A = 3 C = 6 H = 24

V = 1/2 x 3 x 6 x 24 = 216 cubic feet

Since there are 20 pounds of snow per cubic foot, you multiply the cubic feet (216) by the pounds of snow per cubic foot (20):

216 x 20 = 4,320 pounds

4 0
3 years ago
Carla is arranging square patches of grass on her rectangular lawn her lawn is 10 yards wide and 3 and 1/2 yards long how many s
Paraphin [41]

Answer:

I don't know if this is correct but wouldn't it be 560?

Step-by-step explanation:

If you have 10 on one side, you divide 10 by 1/4 to get 40. So you need 40 blocks to fill one side, and 3 1/2 on the other only needs 14. 14*40=560.

8 0
3 years ago
Find an n^th degree polynomial with real coefficients satisfying the given conditions. n = 3; -2 and 2 i are zeros; f(-1) = 15.
Ira Lisetskai [31]
So, n = 3, is a 3rd degree polynomial, roots are -2 and 2i

well 2i is a complex root, or imaginary, and complex root never come all by their lonesome, their sister is always with them, the conjugate, so if 0+2i is there, 0-2i is there too

so, the roots are -2, 2i, -2i

now... \bf \begin{cases}
x=-2\implies x+2=0\implies &(x+2)=0\\
x=2i\implies x-2i=0\implies &(x-2i)=0\\
x=-2i\implies x+2i=0\implies &(x+2i)=0
\end{cases}
\\\\\\
(x+2)\underline{(x-2i)(x+2i)}=0\\\\
-----------------------------\\\\
\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x+2)[x^2-(2i)^2]=0\implies (x+2)[x^2-(2^2i^2)]=0
\\\\\\
(x+2)[x^2-(4\cdot -1)]=0\implies (x+2)(x^2+4)=0
\\\\\\
x^3+2x^2+4x+8=0

now, if we check f(-1), we end up with 5, not 15
hmmm

so, how to turn our 5 to 15? well, 3*5, thus

\bf 3(x^3+2x^2+4x+8)=f(x)\implies 3(5)=f(-1)\implies 15=f(-1)

usually, when we get the roots, or zeros, if any common factor that is a constant is about, they get in a division with 0 and get tossed, and aren't part of the roots, thus, we can simply add one, in this case, the common factor of 3, to make the 5 turn to 15
6 0
3 years ago
Which of the following phrases can be used to represent -11? the opposite of -11 eleven greater than zero eleven below zero posi
Rama09 [41]

Answer:

the opposite of -11 eleven greater than zero eleven below zero positive eleven

Step-by-step explanation:

5 0
3 years ago
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