3 years ago

Factor. x^2−10x−11

1 answer:

8 0

Xjsksnsosnsosnsosnd. Didnrjebs didneisneiw sjs did god Factor. x^2−10x−11

(x+11)(x−1)

(x+11)(x+1)

(x−11)(x+1)

(x−11)(x−1)

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notka56 [123]

Answer:

Population after $t\ years=250000\times (0.985)^t$

Step-by-step explanation:

If $P$ is the initial amount, $r$ is the annual rate of decrease then after $t$ years the remaining amount $(A)$ will be given by

$A=P(1-\frac{r}{100})^t$

Here $P=250000, r=1.5\%\\\\A=250000(1-\frac{1.5}{100})^t\\\\A=250000(1-0.015)^t\\\\A=250000\times (0.985)^t$

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3 years ago

sweet-ann [11.9K]

Answer: 40x

First, let's find f(2x)

$f(2x)=4(2x)=8x$

Using this, let's find g(f(2x)):

$g(f(2x))=g(8x)=5(8x)=40x$

That's the answer. Let me know if you need any clarifications, thanks!

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3 years ago

Aleks04 [339]

Left side goes up 5 right side goes up 7

The rate of change between 5,15 is 10

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3 years ago

tatyana61 [14]

Answer:

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Step-by-step explanation:

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3 years ago

harkovskaia [24]

It would be 11,000 to the nearest thousand.

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3 years ago