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Nana76 [90]
3 years ago
5

Factor. x^2−10x−11

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0
Xjsksnsosnsosnsosnd. Didnrjebs didneisneiw sjs did god Factor. x^2−10x−11

(x+11)(x−1)

(x+11)(x+1)

(x−11)(x+1)

(x−11)(x−1)
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Two angles are supplementary one angle measure 12 more than the other find the measures
Furkat [3]
We have a + b = 180 and a = 12 + b;
Then, 12 + b + b = 180;
12 + 2b = 180;
2b = 168;
b = 84;
a = 12 + 84;
a = 96;
5 0
3 years ago
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
Planes Q and R intersect. Lines d and c are vertical on plane R and form a right angle with line B on plane Q. Line B is horizon
Akimi4 [234]

Answer:

C. line d

Step-by-step explanation:

Two parallel lines are lines that do not meet even with continuous extension of their length. While two lines are perpendicular when they form a right angle to each other at the point where they meet.

In the given question, the only figure that would be parallel to line c is line d. Line a is not parallel to line c (since it is slightly diagonal, it would intersect line c at a point) and line B is perpendicular to line c (since it is horizontal to plane Q), same as plane Q. So that lines c and d are parallel to each other.

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