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dangina [55]
3 years ago
6

Ill attach a pic because I dont know how to write this out

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Distances:

<h3>a = π / 2 , b = π , c = 3π /2</h3>

Heights:

<h3>d = 1 , e = 0 , f = - 1</h3>

Formula used = for distance , we use:

\frac{theta}{360}  \times 2\pi \: r

length of arc = 1 m

\frac{ \frac{\pi}{2} }{2\pi}  \times 2\pi \times 1

a \:  =  \:  \frac{\pi}{2}

B = \frac{\pi}{2\pi}  \times 2\pi \times 1

= \pi

C = \frac{ \frac{3\pi}{2} \times 2\pi }{2\pi}

=  \frac{3\pi}{2}

Heights:

If theta = π / 2 , d = 1

If theta = π , e = 0

If theta = 3π/2 , f = - 1

<h2>Please see the attached picture..</h2>

hope this helps..

Good luck on your assignment..

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Slav-nsk [51]

Answer:

x-intercept: (3,0)

y-intercept: (0,-4)

Step-by-step explanation:

To find the x and y-intercepts, we first need to understand what they are. X and y-intercepts are points on the line that passes through the x-axis and y-axis. When a point is an x-intercept, it passes through the x-axis. This means the x-coordinate is an integer, while the y-coordinate is always 0. This can be denoted by (x,0). When a point is a y-intercept, it passes through the y-axis. This means the y-coordinate is an integer, while the x-coordinate is always 0. This can be denoted by (0,y).

Now that we know what x and y-intercepts are, we can plug in x=0 and y=0 to find the intercepts.

x-intercept

4x-3y=12            [plug in y=0]

4x-3(0)=12          [multiply]

4x-0=12              [add both sides by 0]

4x=12                 [divide both sides by 4]

x=3

---------------------------------------------------------------------------------------------------------

y-intercept

4x-3y=12            [plug in x=0]

4(0)-3y=12         [multiply]

0-3y=12             [subtract both sides by 0]

-3y=12               [divide both sides by -3]

y=-4

Therefore, the x-intercept is (3,0) and y-intercept is (0,-4).

3 0
3 years ago
HELP ASAP.<br><br> Please solve.<br><br> 2 plus or minus the square root of negative 36 over 2
AVprozaik [17]

Answer:

The expression is not defined in a set of real numbers.

The square root of a negative number is not defined in the set of real numbers.

5 0
3 years ago
Solve the quadratic. x^2+8x+3=0
Reil [10]
Factor
find wht 2 numbers add to 8 and multiply to 3
none do

use quadratic formula which can be used when
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}}-4ac }{2a}

a=1
b=8
c=3

x=\frac{-8+/- \sqrt{8^{2}-4(1)(3)} }{2(1)}
x=\frac{ -8+/- \sqrt{64-12} }{2}
x=\frac{ -8+/- \sqrt{52} }{2}
x=\frac{ -8+/- 2 \sqrt{13} }{2}
x=-4+/- \sqrt{13}

x=-4+ \sqrt{13} or x=-4- \sqrt{13}
aprox x=-7.60555 or x=-0.394449





6 0
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spayn [35]

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Step-by-step explanation:

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uranmaximum [27]

Answer:

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Step-by-step explanation:

The formula for finding the area of a triangle is 1/2b x h

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I could be wrong here so

Here's a little tip:

I can tell you're using G.oogle Forms, so you can press ctrl + U and find the answers in the code

8 0
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