Step-by-step explanation:
<h3>
<em><u>Given</u></em><em><u>:</u></em></h3>
Length of the rectangle = 6.5 m
Width of the rectangule = 7.3 m
<h3>
<em><u>Then</u></em><em><u>:</u></em></h3>
<u>First</u><u> </u><u>case</u><u>,</u>
Area of the rectangle
= length × width
= 6.5 m × 7.3 m
= <em><u>47.45</u></em><em><u> </u></em><em><u>s</u></em><em><u>q</u></em><em><u>.</u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>i</u></em><em><u>)</u></em>
<u>Second</u><u> </u><u>case</u><u>,</u>
Perimeter of the rectangle
= 2(length + width)
= 2(6.5 + 7.3)m
= 2 × 13.8 m
= <em><u>27</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>ii</u></em><em><u>)</u></em>
Answer:
Simplified: 0.024
Step-by-step explanation:
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
He would need a 93% on his fourth exam.
94+89+96+93= 372, 372 divided by 4= 93
I don’t really understand this put a person with genius role is answering so i hope you get your answer! goodluck
