The answer . to your question is yes
A.) Yes, every input is paired with exactly 1 output.
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Explanation:</h2><h2>
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In this case, we hace the following exponential function:
![f(x)=ab^x](https://tex.z-dn.net/?f=f%28x%29%3Dab%5Ex)
Where:
![a:Initial \ value \\ \\ b:the \ base](https://tex.z-dn.net/?f=a%3AInitial%20%5C%20value%20%5C%5C%20%5C%5C%20b%3Athe%20%5C%20base)
The base
because 1 raised to any power leads the result of 1. That is:
![1^2=1 \\ \\ 1^3=1 \\ \\ 1^{\sqrt{3}}=1 \\ \\ \\ In \ conclusion: \\ \\ 1^{n}=1, \ \text{n any real number}](https://tex.z-dn.net/?f=1%5E2%3D1%20%5C%5C%20%5C%5C%201%5E3%3D1%20%5C%5C%20%5C%5C%201%5E%7B%5Csqrt%7B3%7D%7D%3D1%20%5C%5C%20%5C%5C%20%5C%5C%20In%20%5C%20conclusion%3A%20%5C%5C%20%5C%5C%201%5E%7Bn%7D%3D1%2C%20%5C%20%5Ctext%7Bn%20any%20real%20number%7D)
If so, then we won't get an exponential function, but a constant function:
![f(x)=a](https://tex.z-dn.net/?f=f%28x%29%3Da)
Answer: c
Step-by-step explanation:
divide 5.20 by 6 and you will get 0.87