Step-by-step explanation:
Wendy
-20 = x/2 + 7
-20 -7 = x/2 + 7 -7
-27 = x/2
-54 = x
x = -54
because it's math rule
Answer: The fraction of the gifts were for birthdays = 
.
Step-by-step explanation:
Given: fraction of gifts for weddings = 
fraction of gifts for baby showers = 
Rest of the gifts = 
![=\dfrac{100-30-37}{100}\ \ \ [\text{Making like fractions}]\\\\=\dfrac{100-67}{100}\\\\=\dfrac{33}{100}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B100-30-37%7D%7B100%7D%5C%20%5C%20%5C%20%5B%5Ctext%7BMaking%20like%20fractions%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B100-67%7D%7B100%7D%5C%5C%5C%5C%3D%5Cdfrac%7B33%7D%7B100%7D)
Hence, the fraction of the gifts were for birthdays = .
Remark
I didn't know this was a calculus question. How dumb of me.
f(x + h) - f(x)
==========
x + h - h
50/6 - 51/6 =( -1/6+ h)/h
The h's will disappear when the limit is taken.
answer - 1/6 which is A. If anyone else answers take their answer.
The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.
We can begin by rearranging this into multiplication:
Now we can factor the numerators and denominators:
The factors
(x+4) and
(x+2) cancel out, leaving us with:
Our answer comes out to be:
or
Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are
x ≠ -4, -3, -2, -1, 4
