F: R → R is given by, f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1
So, f(1.2) = f(1.9), but 1.2 ≠ 1.9
f is not one-one
Now, consider 0.7 ε R
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ε R such that f(x) = 0.7
So, f is not onto
Hence, the greatest integer function is neither one-one nor onto.
The answer was quite complicated but I hope it will help you.
Answer:yes
Step-by-step explanation:
because 0.89 is a very small number so itd be reasonable for it to be a large number
The answers are as follows.
a. 9x
In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as
64^3x = (4^3)^3x = 4^9x
Which gives you the first answer.
b. 10
Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.
16^5/2 = (2^4)^5/2 = 2^20/2 = 2^10
c. Sqrt(7.31)
This one is more simple. Raising something to a 1/2 power (.5) is the same as taking the square root.
The answer is the √26 and -√26. Look at the picture for explanation.