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Anuta_ua [19.1K]
3 years ago
7

Can someone plz help me

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

a = 6, b = 5, c = 3

Step-by-step explanation:

Given

\frac{1}{6} ÷ \frac{3}{5}

Leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

\frac{1}{6} × \frac{5}{3}

Compare with

\frac{1}{a} × \frac{b}{c}

To obtain a = 6, b = 5 and c = 3

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Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
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Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

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To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

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[As secƟ = 1/cosƟ)

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Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

#SPJ9

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