The following graph shows the low temperatures for the past six nights. What was the range of temperatures for the six nights?
1 answer:
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Given:
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)
μ = $3120, population mean
σ = $677, population standard deviation.
The population is normally distributed.
n = 20, sample size.
At the 95% confidence level, the confidence interval is
1.96(σ/√n) = 1.96(677/√20) = 296.71
Th confidence interval for the mean is
($2823.29, $3416.71)
Answer: ($2823.29, $3416.71)
Answer:
See Below.
Step-by-step explanation:
Paragraph Proof:
We are given that ∠1 ≅ ∠4. ∠1 and ∠4 are alternate exterior angles. Since they are congruent, by the Alternate Exterior Angles Converse, the two lines being cut by the transversal must be parallel. Then by the Alternate Interior Angles Theorem, ∠3 ≅ ∠2.
2-Column Proof
Statements Reasons:
1) Given
2) Alternate Exterior Angles Converse
3) Alternate Interior Angles Theorem
I would write a flowchart as well, but unfortunately, I never learned it that way.