Answer:
payload
Explanation:
Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.
The encapsulating security payload (ESP) protocol is a standard protocol that provides secrecy for the contents (data) transmitted via network communications, as well as system-to-system authentication and data integrity verification so as to prevent unauthorized access.
Basically, the encapsulating security payload (ESP) protocol is a transport layer protocol that provides data confidentiality, integrity and authentication in IPv6 and IPv4 protocols.
Click where you want to insert the picture on the slide.
On the Insert tab, in the Images group, click Pictures.
In the dialog box that opens, browse to the picture that you want to insert, click that picture, and then click Insert.
The principle or element of layout design is highlighted in an event poster in option i: The headline.
<h3>What are the elements of page layout?</h3>
The poster is known to be one that often uses a kind of hierarchy and centered text alignment as its element.
Note that it is one whose Lines of use is said to be made up of different kinds of type styles, sizes and others.
The simple elements of an advertising poster is made up of:
1. The headline.
2. The sub-head.
3. The body copy.
4. The caption.
The elements of page layout are visual hierarchy, visual flow, and others. Hence, the principle or element of layout design is highlighted in an event poster in option i: The headline.
Learn more about layout design from
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#SPJ1
Answer:
listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
listString = [ ]
for i in range(14):
if listNumbers[i]%2!=0 and listNumbers[i]%5==0:
listString.append("five odd")
elif listNumbers[i]%5==0 and listNumbers[i]%2==0:
listString.append("five even")
elif listNumbers[i]%2==0:
listString.append("even")
elif listNumbers[i]%2!=0:
listString.append("odd")
print(listNumbers)
print(listString)
Explanation:
In python programming language;
- Create two lists
- The first is a list of numbers and initialize it with random values: listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
- The second list is empty and will hold the string values listString = [ ]
- Use a for loop to iterate over all the elementts in the list of numbers
- Use the modulo operator (%) to chech for multiples of particular numbers as stipulated by the question
- Use combination of if/elif statements for each condition
- Use the .append method to add the elements into the list of strings
- finially output both lists
See attached code and output
