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OLga [1]
3 years ago
12

The ________________ Act requires Internet sales to be treated in the same way as mail-order sales (e.g., collect sales tax from

customers residing in same state as business).
Computers and Technology
1 answer:
BARSIC [14]3 years ago
5 0

Answer:

Internet Tax Freedom Act

Explanation:

The Internet Tax Freedom Act was signed into law in 1998 by President Bill Clinton and has since been reviewed until the Permanent Internet Tax Freedom Act was passed into law on the 9th of June, 2015 by President Barrack Obama.

The Act requires that internet sales are equally treated as mail-order sales.

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Which of these is NOT one of the three parts to the event-handling mechanism in Java?
Tamiku [17]

Answer:Event action

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5 0
3 years ago
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
3 years ago
20
denis-greek [22]

Answer:

true

Explanation:

because my 8 ball said so

6 0
3 years ago
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