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Black_prince [1.1K]
3 years ago
5

If n is a term of the sequence 2,5,8,11,..., which expression would give the value of n?

Mathematics
2 answers:
Wittaler [7]3 years ago
5 0
The term of the sequence is eleven 11
Elina [12.6K]3 years ago
4 0


First Find the difference between the numbers, in this case it's 3, then multiply it by n, so first you have 3n. Now, subtract this number from the first term, and put it on the end of your equation. Here we get -1. So the answer is 3n-1
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615.44 to the nearest hundredth
Leya [2.2K]
When rounding, look to the next place to the right of what you are rounding to... for example if you are rounding to the nearest hundredth, look to the thousandths place to see if the hundredths place rounds up or down. Since your number, 615.44 stops on the hundredths place, the thousandths place is automatically zero, so your number stays the same.

615.44
3 0
3 years ago
Help me out? tysvm!!!
Sophie [7]

Answer: 103

Step-by-step explanation:

8 x 6.5 = 52,

52 + 8 = 60 (pints in total)

there are 2 cups in 1 pint so 60 x 2 = 120

120 - 17 = 103

3 0
2 years ago
ANSWER !! <br> ILL GIVE 40 POINTS !!<br> DONT SKIP :(( <br> PLUS BRAINLIEST !
Likurg_2 [28]

Answer:

85

Step-by-step explanation:

10x13=130, 9x5=45, 130-45=85

4 0
2 years ago
-5•3 = 3 • -5<br><br> Name the property that justifies the statement
algol13

Answer:

commutative property of multiplication

Step-by-step explanation:

3 0
3 years ago
Which expression is equivalent to the following complex fraction?
user100 [1]

The equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

<h3>How to determine the equivalent fraction?</h3>

The fraction is given as:

(1 + \frac{1}{y}) \div (1-\frac 1y)

Take the LCM

\frac{y + 1}{y} \div \frac{y-1}y

Express as products

\frac{y + 1}{y} \times \frac{y}{y-1}

Evaluate the product

\frac{y + 1}{y-1}

Hence, the equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

Read more about equivalent expression at:

brainly.com/question/24734894

#SPJ1

4 0
2 years ago
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