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zloy xaker [14]

3 years ago

11

The length of a rectangle is twice it's width . If the area of the rectangle is 50 yd(second power) find its permeter

2 answers:

pshichka [43]3 years ago

6 0

10 yards is the length and 5 yards is the width which to find the area you would multiply length times width which is 10 • 5 = 50 that's the area of the rectangle and the perimeter you would add all for sides the widths and the length which is 10+10+5+5=30 yards

Juliette [100K]3 years ago

4 0

The length would be 10yds and the width would be 5yds as they multiply together to give 50yds squared as an area and 10 is twice the amount of 5. So that means the perimeter would be 10+10+5+5 which = 30yds.

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Need help with this math problem

AysviL [449]

Answer:

CAB = 54

ABC = 21

ACB = 105

DCB = 75

Step-by-step explanation:

18x - 15 = (13x - 11) + (4x + 1)

18x - 15 = 17x - 10

x = 5

CAB = 13x - 11 = 13(5) - 11 = 65 - 11 = 54

ABC = 4x + 1 = 4(5) + 1 = 20 + 1 = 21

ACB = 180 - (CAB + ABC) = 180 - (54 + 21) = 180 - 75 = 105

DCB = 180 - ACB = 180 - 105 = 75

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Licemer1 [7]

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alukav5142 [94]

Answer:

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Answer:

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pav-90 [236]

Answer:

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