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inn [45]
3 years ago
12

Please help me my 3rd grade teacher never though got me how to divide

Mathematics
1 answer:
ankoles [38]3 years ago
7 0
6.  300
7.  20
9.  300
10. 800
12. 800
13.  700
15. 700
16. 700
. 
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What is 8x over 2y ?
Nana76 [90]

Answer:

6 2/3.. i think

Step-by-step explanation:

hopefully u understand my messy handwriting

4 0
2 years ago
What is the product?( square root 3x+ square root 5) (square root 15x+ 2 square root 30)
hichkok12 [17]
(\sqrt{3x}+\sqrt5)\cdot(\sqrt{15x}+2\sqrt{30})\\\\=(\sqrt{3x})(\sqrt{15x})+(\sqrt{3x})(2\sqrt{30})+(\sqrt5)(\sqrt{15x})+(\sqrt5)(2\sqrt{30})\\\\=\sqrt{(3x)(15x)}+2\sqrt{(3x)(30)}+\sqrt{(5)(15x)}+2\sqrt{(5)(30)}\\\\=\sqrt{45x^2}+2\sqrt{90x}+\sqrt{75x}+2\sqrt{150}\\\\=\sqrt{9x^2\cdot5}+2\sqrt{9\cdot10x}+\sqrt{25\cdot3x}+2\sqrt{25\cdot6}\\\\=\sqrt{9x^2}\cdot\sqrt5+2\sqrt9\cdot\sqrt{10x}+\sqrt{25}\cdot\sqrt{3x}+2\sqrt{25}\cdot\sqrt6
=3x\sqrt5+2\cdot3\sqrt{10x}+5\sqrt{3x}+2\cdot5\sqrt6\\\\=3x\sqrt5+6\sqrt{10}+5\sqrt{3x}+10\sqrt6
3 0
3 years ago
Read 2 more answers
Put these fractions from smallest to greatest<br><br>6/5, 8/15, 1/4
valkas [14]
1/4, 8/15, 6/5
One way to figure this out is to divide the fractions and find which number is bigger
Or you should know 1/4= .25 , 8/15 is around half or .5 and 6/5  the numerator is larger than the denominator, so it would be bigger than 1 <span />
3 0
3 years ago
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Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
If h(x) = -3x – 10, find h(-3).<br> 0-19<br> On1<br> 01<br> 23
Alex_Xolod [135]
-1. Plug in -3 for x which makes 9-10 so -1
4 0
3 years ago
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