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mrs_skeptik [129]
3 years ago
8

Henry is dividing a length of rope into pieces that are each foot long. How many pieces will he get from 8 feet of rope?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ Henry will get 8 pieces from 8 ft of rope.

If 1 ft of rope is equal to one piece, that means that 8 ft is equal to 8 pieces.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

sammy [17]3 years ago
4 0

Answer:

8 pieces of rope.

Step-by-step explanation:

8/1=8, so he has 8 pieces in an 8 feet long rope.

Hope this helps!

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Write the ratio 2/11 to 7/11 as a fraction in the lowest terms.
Svetradugi [14.3K]
The lowest term for  2/11 is  2/11 because  it can not be  reduced. The lowest term for  7/11 is 7/11 to because  it can not be reduced

8 0
3 years ago
Given f(x) =
inysia [295]

The end behavior of the given function (range) is x< 4 or x > 4. So, f(x) < 4 or f(x) > 4. The solution in interval notation is \mathbf{(-\infty, 4) \cup (4, \infty)}.

The last option is correct.

<h3>What is the range of the function?</h3>

The end behavior of the given function f(x) = (8x+1)/2x-9 wants us to identify the range of the given function.

The range is the set of values of the dependent variable for which a function is defined. The function range is the combined domain of the inverse function.

From the information given:

\mathbf{f(x) = \dfrac{8x +1}{2x -9 }}

Inverse of \mathbf{\dfrac{8x +1}{2x -9 }} becomes \mathbf{f(x) = \dfrac{1+9x}{2(-4+x) }}

The domain of the inverse is x< 4 or x > 4. So, f(x) < 4 or f(x) > 4. Now, representing the solution in interval notation, we have:

\mathbf{(-\infty, 4) \cup (4, \infty)}

Learn more about the range of a given function here:

brainly.com/question/1466393

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6 0
2 years ago
Find the answer to the question please 16t^4/8t
sammy [17]

Answer:

STEP

1

:

Equation at the end of step 1

 ((16 • (t4)) -  23t2) +  1

STEP

2

:

Equation at the end of step

2

:

 (24t4 -  23t2) +  1

STEP

3

:

Trying to factor by splitting the middle term

3.1     Factoring  16t4-8t2+1

The first term is,  16t4  its coefficient is  16 .

The middle term is,  -8t2  its coefficient is  -8 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   16 • 1 = 16

Step-2 : Find two factors of  16  whose sum equals the coefficient of the middle term, which is   -8 .

     -16    +    -1    =    -17

     -8    +    -2    =    -10

     -4    +    -4    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  -4

                    16t4 - 4t2 - 4t2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   4t2 • (4t2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (4t2-1)

Step-5 : Add up the four terms of step 4 :

                   (4t2-1)  •  (4t2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

3.2      Factoring:  4t2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  4  is the square of  2

Check : 1 is the square of 1

Check :  t2  is the square of  t1

Factorization is :       (2t + 1)  •  (2t - 1)

Trying to factor as a Difference of Squares:

3.3      Factoring:  4t2 - 1

Check :  4  is the square of  2

Check : 1 is the square of 1

Check :  t2  is the square of  t1

Factorization is :       (2t + 1)  •  (2t - 1)

Multiplying Exponential Expressions:

3.4    Multiply  (2t + 1)  by  (2t + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2t+1)  and the exponents are :

         1 , as  (2t+1)  is the same number as  (2t+1)1

and   1 , as  (2t+1)  is the same number as  (2t+1)1

The product is therefore,  (2t+1)(1+1) = (2t+1)2

Multiplying Exponential Expressions:

3.5    Multiply  (2t-1)  by  (2t-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2t-1)  and the exponents are :

         1 , as  (2t-1)  is the same number as  (2t-1)1

and   1 , as  (2t-1)  is the same number as  (2t-1)1

The product is therefore,  (2t-1)(1+1) = (2t-1)2

Final result :

 (2t + 1)2 • (2t - 1)2

Step-by-step explanation:

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disa [49]

Answer:

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Step-by-step explanation:

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3 years ago
The polynomial p(x)=7^3-7x-6 has a known factor of (x+1) rewrite p(x) as a product of linear functions
san4es73 [151]

Answer:

p(x)=(x+1)(x+2)(x-3).

Step-by-step explanation:

Note: The given function is not correct.

Consider the given polynomial is

p(x)=x^3-7x-6

It is given that (x+1) is a factor of given function.

Using synthetic division, divide P(x) by (x+1) as shown below.

-1  |     1      0     -7      -6

    |           -1       1       6

--------------------------------------

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--------------------------------------

Bottom line represents the coefficients of quotient except the last element because it is remainder. So, the given function can be written as

p(x)=(x+1)(x^2-x-6)

p(x)=(x+1)(x^2-3x+2x-6)

p(x)=(x+1)(x(x-3)+2(x-3))

p(x)=(x+1)(x+2)(x-3)

Therefore, the function as a product of linear functions is p(x)=(x+1)(x+2)(x-3).

7 0
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