Answer: 4in
Step-by-step explanation:
Volume of a cylinder = πR²H
Volume of a cone = 1/3πr²h
πR²H = 1/3πr²h
π is very common so it could be cancelled, so the equation now becomes
R²H = 1/3r²h
3R²H = r²h
Now substitute for the values
h = 3 x 2² x 3
--------------
3²
= 9 x 4/9
= 4in.
Therefore, the height of the cone
h = 4in.
Answer:
Step-by-step explanation:
Let 
.
and
The graph of the two equations are shown in the attachment.
The points where the two graphs intersected are: 
The x-coordinates of the intersection points are the solutions to 
.
Therefore the solutions are:
Answer:
a²/9
Step-by-step explanation:
(27a⁻³) (-⅔) = 27^(-⅔) × (a⁻³)^(-⅔)
= (3³)^(-⅔) × a²
= 3⁻²a²
= a²/9
Answer:
I am sorry but I am not sure of this :(
Answer:
for first parallelogram
Area of parallelogram = b*h= 3.5*2= 7square unit
for second parallelogram
Area of parallelogram = b*h = 1.8 square unit
or, 3*h = 1.8
h= o.6unit
For third parallelogram
Area of parallelogram = b*h = 20.4square unit
4*b= 20.4
b=5.1 unit
Step-by-step explanation:
