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lapo4ka [179]
3 years ago
15

05.01)Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-h

alf ? 3 in by 4 in 6 in by 8 in 12 in by 16 in 1.5 in by 2 in
Mathematics
2 answers:
poizon [28]3 years ago
8 0
Half of 6 is 3
Half of 8 is 4 
so it will be 3 in by 4 in.
andreyandreev [35.5K]3 years ago
3 0

Answer:

3 in by 4 in just toke the test

Step-by-step explanation:

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If the numbers 25, 30 ,40, 48 are in proportion, Middle terms are.....
zubka84 [21]

Step-by-step explanation:

it is 5/6 ..............

3 0
3 years ago
A trapezoid has an area of 35 square inches. It has a base of 8 inches and 6
Liula [17]

the height of the trapezoid of 5, i think.

my work:

i used this formula: 2 x a + b / A

so, you plug in what you know.

2 x 8+6 / 35 = 5

5 0
3 years ago
What is the fraction that is equal to 0.534
Mandarinka [93]

Answer:

267/500

Step-by-step explanation:

0.534 = 534 / 1000

Simplify to 267/500

3 0
3 years ago
Read 2 more answers
Dylan drank 5.2 ounces of water before soccer practice, and 12.9 ounces after practice. Before he drank any water, there were 28
Elan Coil [88]

Answer:

x=28-5.2-12.9, 9.9 ounces of water remaining.

Step-by-step explanation:

<u>Given:</u>

Dylan drank 5.2 ounces of water before soccer practice, and 12.9 ounces after practice.

Before he drank any water, there were 28 ounces of water in the container.

<u>Question asked:</u>

Which expression can be used to find the amount of water remaining?

<u>Solution:</u>

Let x the amount of water remaining.

Total quantity of water in the container = 28 ounces

Before practice, Dylan drank = 5.2 ounces

After practice, Dylan drank = 12.9 ounces

Remaining amount of water = Total quantity of water in the container - Amount of water is drunk before practice - Amount of water is drunk before practice

x=28-5.2-12.9\\ \\ x=28-18.1\\ \\ x=9.9\ ounces

Thus, 9.9 ounces of water remaining in the container.

8 0
3 years ago
The rectangular coordinates of a point are given. Find the polar coordinates ​(r,theta​) of this point with theta expressed in r
alexandr402 [8]

Answer:}

In polar coordinates P is

P  ( 12 ; 2.618 )  

Step-by-step explanation:

The point (ectangular coordinates)  

P ( -6√3  ;   6 )       P  (  x ; y )

Polar coordinates   P ( r  ;  θ )

x = r cos θ

y = r sin θ                  r > 0    and     0  ≤ θ ≤ 2π

Then

r  =  √ (x)² + (y)²        r  =  √(36)²*3 +( 36)²       r = √144

r  =  12   (hypothenuse module always positive)

The point   P  ( -6√3  ;   6 )   is in second cuadrant  between 90° and 180°

angle between  r  and horizontal axis x  is equal to θ

tan α =  l.opp/ l.adj.    tan θ =  y/x       tan θ = - 6 /6√3

tan α = - 1/√3

Then α  =  180⁰ - 150⁰  = 30⁰  or     θ =  150⁰

to express that value in radians we have :

1 π radian      =   180⁰         ⇒   3,1416   radians  =  180⁰

                                                      x ??                  =   150⁰

x =  radians

Finally the point is   P  ( 12 ; 2.618 )  

6 0
3 years ago
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