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3 years ago

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05.01)Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-h

alf ? 3 in by 4 in 6 in by 8 in 12 in by 16 in 1.5 in by 2 in

2 answers:

poizon [28]3 years ago

8 0

Half of 6 is 3
Half of 8 is 4
so it will be 3 in by 4 in.

andreyandreev [35.5K]3 years ago

3 0

Answer:

3 in by 4 in just toke the test

Step-by-step explanation:

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The game piece has 12 sides labeled 1 to 12 what is the probability of rolling on 11

maks197457 [2]

Answer:

The probability would be 1/12 because there are 12 sides and there is only 1 11.

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Step-by-step explanation:

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4 years ago

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Which sum or difference is modeled by the algebra tiles? A. (x2 4x − 2) (x2 − 2x − 4) = 2x2 2x 2 B. (x2 4x − 2) (x2 2x 4) = 2x2

dimulka [17.4K]

Answer:

Because (-x²+2x+3)+(-x²-2x-1) = -x²+2x+3-x²-2x-1 = -2x²+2

Step-by-step explanation:

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2 years ago

According to the rational root theorem, which answer is not a possible rational root of x^3+9x^2-x+8=0

Readme [11.4K]

Answer:

6

Step-by-step explanation:

The rational root theorem states that the roots must be factors of p/q

where p is the constant and q is the coefficient of the highest order term

p = 8 which has factors ±1, ±2,±4,±8

q = 1 which has factors ±1

The possible roots are ±1, ±2,±4,±8

--------------------

±1

which simplifies to

±1, ±2,±4,±8

6 is not a possible root

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3 years ago

He curriculum committee at Larchmont High School wants to offer a new elective course next year. They decide to survey Larchmont

Mars2501 [29]

Answer:

I think Athletics Hope this helps

Step-by-step explanation:

8 0

3 years ago

Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.

ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is $-9 x \times x \times x \times(x-7) \times(x+3)$

<u>Solution:</u>

Given, polynomial equation is $-9 x^{5}+36 x^{4}+189 x^{3}$

We have to find the factored form of the above given polynomial equation.

Let us solve it by grouping.

Now, take the polynomial ⇒ $-9 x^{5}+36 x^{4}+189 x^{3}$

By taking common term out, we get

$\rightarrow-9 x^{3}\left(x^{2}-4 x-21\right)$

$\rightarrow-9 x^{3}\left(x^{2}-(7-3) x-7 \times 3\right)$

Grouping the terms we get,

$\rightarrow-9 x^{3}\left(\left(x^{2}-7 x\right)+(3 x-7 x^3)\right)$

Taking common terms out from each group,

$\rightarrow-9 x^{3}(x(x-7)+3(x-7))$

$\Rightarrow-9 x^{3}((x-7)(x+3))$

$\rightarrow-9 x \times x \times x \times(x-7) \times(x+3)$

Thus the factored form of polynomial is found out

4 0

3 years ago