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oee [108]
2 years ago
12

Can someone help me with this?

Mathematics
1 answer:
Zinaida [17]2 years ago
6 0

Answer:

ccjchdhsgjdhkdhkdykdhkdhkzhkxhmdhmdhkxhmf

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Show work please I need help asap
rosijanka [135]

Answer:

12. -11

13. 2

Step-by-step explanation:

12. First recall the order of operations (BEDMAS): Brackets, Exponents, Division, Multiplication, Addition, Subtraction

For question 12 there is a division and its priority is before other operations in the equation so you must divide 16/-2 first which gives you -8.

From there because addition and subtraction is on the same level of order, you would do the question straight as it is shown (but replace 16/-2 with -8.

Your new equation is -10-8+7 = -11

13. follow the same as above using BEDMAS. It may help to look at it with additional brackets: ((-68)/(-4)) + ((5 x (-3))

  • keep in mind there’s an addition between the two

Division and multiplication is on the same level in BEDMAS so first divide -68/-4 = 17

Second multiply 5 x -3 = -15

Now you can combine the two answers using addition: 17 + (-15) = 2

5 0
2 years ago
-37= n/23<br> what is n?
Vlada [557]
-37 = <u>n
</u>       23
<u>
</u>to solve for n, undo what is happening to the n. if the n is being divided by 23 to get -37, then multiply both sides by 23 to figure out what n is. 
<u>
</u>-37 * 23 = <u>n * 23 
</u>                   23
<u>
</u>-851 = n
3 0
3 years ago
Read 2 more answers
Salim had 24 homework problems.
lesantik [10]

Answer:

so im guessing  the remainder of hw problems->

Step-by-step explanation:

24-7 =17 math problems left from doing some lunch

17-7= 10 math so its 10 math problems left

6 0
3 years ago
Solve for c <br><br> a= b+c/d
castortr0y [4]
B+c/d=a  subtract b from both sides

c/d=a-b multiply both sides by d

c=d(a-b) or if you prefer

c=ad-bd

Note: if you meant a=(b+c)/d, multiply both sides by d

b+c=ad  subtract b from both sides

c=ad-b
4 0
3 years ago
I need a 5 digital number
azamat

Answer:

What do you mean by that?

Step-by-step explanation:

5 0
3 years ago
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