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irakobra [83]
3 years ago
13

If an item is purchased at $500 and it’s value increases at a rate of 5% per year what is the value after four years

Mathematics
1 answer:
qaws [65]3 years ago
6 0

The value of $500 after four years is $610

<u>Step-by-step explanation:</u>

It is given that, the value of $500 increases at a rate of 5% per year.

The exponential formula is given by y = ab^{x}.

where,

  • a is the initial  amount.
  • b is the growth factor .

The growth factor b is replaced by either (1 + r) or by (1 - r).

where, r is the rate per year.

b= (1+r) represents the increase in growth rate.

b= (1-r) represents the decrease in growth rate.

Here, the growth rate is increased. So the formula is given by y = a(1+r)^{n}

where,

  • The initial amount, a = 500.
  • Rate, r = 5% = 5/100 = 0.05
  • Number of years, n= 4.
  • y = value of the item after 4 years

<u>To find y value :</u>

⇒ y = 500(1+0.05)^{4}

⇒ y = 500 (1.05)^{4}

⇒ y = 500 \times 1.22

⇒ y = 610

 Therefore, the value of the item after four years is $610.

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Answer:

$16

Step-by-step explanation:

90m+80m=1360

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Select all of the true statements about the standard deviation of a quantitative variable. 1. Standard deviation is resistive to
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Answer:

Considering the first statement

Standard deviation is resistive to unusual values    

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Considering the second  statement    

The standard deviation of a set of values is equal to 0 if and only if all of the values are the same.

This statement is true because standard deviation is the numeric measure of deviation of the each observation from the mean.

Considering the third  statement

Standard deviation is never negative.

This statement is true because standard deviation is the numeric measure of deviation of the each observation from the mean.

Considering the fourth statement

Changing the units of a set of values (e.g., converting from inches to feet) does not affect its standard deviation

 This statement is false because standard deviation is the numeric measure of deviation of the each observation from the mean

Considering the fifth  statement

If a set of values has a mean of 0 and a standard deviation that is not 0, then adding a new data point with a value of 0 will have no effect on the standard deviation.

This statement is false because , let take an example

    x     -4 - 3 0 3 4

Generally the mean is mathematically evaluated as

    \= x =  \frac{\sum x_i }{n}

=>   \= x =  \frac{-4+ (- 3)+ 0 + 3 + 4 }{5}

=>   \= x =  0

Generally the standard deviation is mathematically evaluated as      

     \sigma  =  \sqrt{\frac{\sum (x_ i - \= x )^2}{y} }

      \sigma  =  \sqrt{\frac{ (-4  - 0 )^2 + (- 3 - 0 )^2 + (0 - 0 )^2 + (3 - 0)^2 + (4 - 0 )^2}{5} }

=>        \sigma  = 3.16

Now when zero is removed the standard deviation is  

\sigma_1  =  \sqrt{\frac{ (-4  - 0 )^2 + (- 3 - 0 )^2 + (3 - 0)^2 + (4 - 0 )^2}{4} }

=>   \sigma_1  =  3.54

Since  \sigma  \ne  \sigma _1 the above statement is  false

Considering the sixth  statement

Standard deviation represents how far a group of values are from the mean of those values, on average.

This statement is true because standard deviation is the numeric measure of deviation of the each observation from the mean.

Step-by-step explanation:

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4 0
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The first thing we need to find out is your strategy so we are using algebra right? the first thing your gonna do is find the formula? 
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Solve for n<br> n/5 = 14 <br> Pleas Help
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N
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