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3 years ago

Triangle ABC has the given measures. Solve the triangle(s), if any exist.

Mathematics

1 answer:

Arada [10]3 years ago

4 0

Answer: why is there two a’s?

Step-by-step explanation:

if those are the correct angles then 1 can be formed because every triangle always adds up to 180

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Rainbow [258]

Answer:

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3 years ago

What’s the area of this tile?

dexar [7]

Answer:

A=24

Step-by-step explanation:

Area for triangle = 1/2b(h)

so 1/2(6)8=24

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3 years ago

Which numbers are solutions to the inequality -3x-3<6? Check all that apply

bogdanovich [222]

Answer:

0, 2, and 4.

Step-by-step explanation:

-3x-3≤6

Add 3 on both sides of the inequality.

-3x≤9

Divide both sides of the inequality by -3.

x≥3

The solutions possible for x can be 0, 2, and 4.

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3 years ago

How to do pyramid math

FromTheMoon [43]

Answer:

https://youtu.be/IPvdVCMb5r4

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3 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

Umnica [9.8K]

The statements and their individual answers are not provided in the question. However, please check the explanation given below for the equation.

Step-by-step explanation:

The equation given is $\frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 }$

Divide the leading term of the dividend by the leading term of the divisor: $\frac{2x^{4} }{2x^{2} } = x^{2}$

Multiply it by the divisor: $x^{2} ({2x^{2} -3x +1) = 2x^{4} - 3x^{3} + x^{2}$

Subtract the dividend from the obtained result: $(2x^{4} + 7x^{3} + 18x^{2} + 11x - 2) - (2x^{4} - 3x^{3} + x^{2} ) = (10x^{3} + 17x^{2} + 11x -2)$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{10x^{3}}{2x^{2} } = 5x$

Multiply it by the divisor: $5x (2x^{2} - 3x + 1) = 10x^{3} - 15x^{2} + 5x$

Subtract the remainder from the obtained result: $(10x^{3} + 17x^{2} + 11x -2) - (10x^{3} - 15x^{2} + 5x) = (32x^{2} + 6x - 2)$

Divide the leading term of the obtained remainder by the leading term of the divisor: $\frac{32x^{2} }{2x^{2} } = 16$

Multiply it by the divisor: $16 (2x^{2} - 3x +1) = 32x^{2} - 48x +16$

Subtract the remainder from the obtained result: $(32x^{2} + 6x - 2) - (32x^{2} - 48x +16) = 54x - 18$

Since the degree of the remainder is less than the degree of the divisor, then we are done.

Therefore, $\frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 } = (x^{2} + 5x +16 + \frac{54x - 18}{2x^{2} - 3x +1})$

7 0

3 years ago

Read 2 more answers