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Gnoma [55]
3 years ago
5

Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 35 problems. Each problem is worth either

5 points or 2 points. How can you set up a system of equations to find how many problems of each point value are on the test? Let x = the number of questions worth 5 points. Let y = the number of questions worth 2 points.
A
Mathematics
2 answers:
baherus [9]3 years ago
6 0

<u>Answer:</u>

<h3>x = 10 , y = 25</h3>

<u>Step-by-step explanation:</u>

in the question we are provide with the required variables x , y

Number of problems with 5 points = x

Number of problems with 2 points = y

Total number of problems = 35

from the above details we can find first equation as,

<h3>                                    x + y = 35 -----------------------(A)</h3><h3 />

total points from 5 point questions = 5x

total points from 2 point questions = 2x

Net total points = 100

now with this data we can find second equation as,

<h3>                                    5x + 2y = 100 ------------------------(B)</h3>

solving (A) and (B) gives us value of x and y

multiply (A) with 2 and subtracting it from (B) gives us

3x = 30

x  = 10

y = 35 - x = 35 -10 = 25

<h3 />

Otrada [13]3 years ago
5 0

Answer:

x + y = 35

5x + 2y = 100

Step-by-step explanation:

If x is the number of questions worth 5 points and y is the number of questions worth 2 points.

Now, it is said that there is a total of 35 questions.

So, x + y = 35 ....... (1)

Again, the test worth 100 points.

Hence, 5x + 2y = 100 .......... (2)

Therefore, the equations (1) and (2) are the system of equations to find x and y. (Answer)  

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3 years ago
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4 0
4 years ago
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meriva

Answer:

A

Step-by-step explanation:

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\boxed{3m - 12 > 30 \wedge -6m\geq  24}

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<u>Note: the signal change because we divided by negative number.</u>

4 0
3 years ago
Read 2 more answers
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