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nataly862011 [7]
3 years ago
11

For which of the following compound inequalities is there no solution?

Mathematics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

3m - 12 > 30 and -6m >= 24

Step-by-step explanation:

A. 3m - 12 > 30 and -6m >= 24

3m > 42  and m < = -4

m > 14 and m < = -4

This has no solution

B. -6m >= 12 and m + 5 -18

cannot solve since missing inequality

C. -5m < 20 and 6m > -18

m > -4   and m > -3

solution m > -3

D. -4m - 10 <= -22 and 6m - 8 >= 22

-4m < = -12  and 6m > = 30

m > = 3   and m > =5

m > = 5

meriva3 years ago
4 0

Answer:

A

Step-by-step explanation:

3m - 12 > 30 \text{ and } -6m\geq  24

\boxed{3m - 12 > 30 \wedge -6m\geq  24}

m>14  \wedge  m\leq -4

There's no solution. It is the first one already. There is no number that is both greater than 14 and less than or equal to -4. That is no solution because there's no m that satisfy the compound inequality.

<u>Note: the signal change because we divided by negative number.</u>

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