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Talja [164]
3 years ago
9

PLEASE HELP ME !!!!!!!!!!!! At Southside Middle School, 40% of the students play an instrument. There are 305 students. How many

students play an instrument? A.40 students B.140 students C.122 students D. 256 students
Mathematics
2 answers:
UkoKoshka [18]3 years ago
5 0

Answer:

40

Step-by-step explanation:

i looked it up         ωФω         ⊕↔⊕

Marianna [84]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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Convert the following percent to a decimal and then to a common fraction. 2%
AlexFokin [52]
Decimal would me .02

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What is YZ?<br><br> Enter your answer as a decimal in the box.
maks197457 [2]

Answer:

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Step-by-step explanation:

The midsegment YZ is half the length of the third side VX , then

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8 0
3 years ago
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I need helpppppppppppp
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Answer:

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Step-by-step explanation:

7 0
4 years ago
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Suppose T is a transformation from ℝ2 to ℝ2. Find the matrix A that induces T if T is reflection over the line y=1/2x
trapecia [35]

Answer:

A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]

Step-by-step explanation:

We have to see how the canonical vectors are transformed throught T. Lets first define T in any basis.

Since T is a reflection, then any element of the line y = x/2 if fixed by T. Therefore T(2,1) = (2,1).

On the other hand, any vector perpendicular to the line direction should be sent to its opposite value. We can take, for example, (-1,2) (note that the scalar product (2,1) * (-1,2) = -2+2 = 0). As a consecuence T(-1,2) = (1,-2). We have

  • T(2,1) = (2,1)
  • T(-1,2) = (1,-2)

By summing the first vector with the double of the second one we get, using linearity

T(0,5) = T( (2,1) + 2(-1,2)) = T(2,1) + 2T(-1,2) = (2,1) + 2(1,-2) = (4,-3)

Hence, T(0,1) = (4/5,-3/5)

Now, we take the second vector and substract it the double of the first one (to kill the second variable)

T(-3,0) = T( (-1,2) - 2*(2,1) ) = T(-1,2) -2T(2,1) = (1,-2)-2(2,1) = (-3,-4)

Therefore, T(1,0) = (1,4/3)

The matrix A induced by  T has in its first column T(1,0) and in its second column T(0,1). We conclude that

A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]

3 0
3 years ago
2(x+5) + 2 = 3 ( 2x - 4)
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2x+10+2=6x-12
4x = 24
x= 6
6 0
3 years ago
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