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nlexa [21]
3 years ago
12

Do you think that the deer only uses the energy that is made by the plant using sunlight?

Biology
1 answer:
Wittaler [7]3 years ago
6 0
Deer are herbivores. Since we know this, we know that deer don't eat meat.

Since deer don't eat meat from other animals or insects, they only eat plant life.

Plants get their energy from the sun through photosynthesis, which makes sugar so the plant can have energy.

The deer then eats the plant which has sugar stored in it and uses that energy to live and function.

-The deer cannot do photosynthesis, so it can't get energy from the sun.
-The deer can't eat meat, so it can't get energy from that either
-The only way for the deer to get energy is by eating the plants

But in the real world, there are a few plants that get energy by eating things, but deer don't eat those plants. Or at least not that I know of.

I hope I helped :)
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No stripe on the head (H) is dominant, a black stripe on the head is recessive. If dad's genotype is Hh, what are the odds that
olga55 [171]

The chance of the offsprings with stripe on head is 50%.

Option A.

<h3><u>Explanation:</u></h3>

Here according to the figures, the male is the brown one which has no stripe on his head as mentioned, and the female is the pink one who has a stripe on her head. The gene for the head stripe is denoted by H.

So the genotype of the father which is given as Hh. He is heterozygous.

The genotype of the mother should be hh as she has stripe and she must be homozygous recessive to have it.

So the gametes from father is H and h. Whereas the gametes from mother is only h.

So the genotype of the offsprings are Hh and hh as 50% each.

So the probability of the offspring being striped head is 50%.

7 0
3 years ago
Which of the following is the average height of the ocean’s surface between high and low tides?
Oxana [17]
The average height of the oceans surface between high and low tides is called the sea level. It is important to know this measurement because with this it is possible that we can calculate the height of anything on the land. Also, we can <span> calculate the height of anything on the land. Also, we can be able to determine whether the oceans are falling or rising through time. 

So the answer is </span><span>Sea level </span>
4 0
3 years ago
Read 2 more answers
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m
Vanyuwa [196]
This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

<span>Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
v=\frac{2\pi{r}}{T}
</span>=\frac{2\pi{r}}{1.88*365.25*86400} m/s, accounting for leap years
=3.371*10^{-8}\pi{r}   m/s

The centripetal force, Fc, generated is
Fc=\frac{mv^2}{r}   
        where m=mass of mars = 6.39*10^(24) kg
=\frac{mv^2}{r}
=\frac{6.39*10^{24}v^2}{r}
=7.26168*10^9\pi^2r

The gravitation pull from the sun, Fg, is given by
Fg=\frac{GMm}{r^2}
    where G=grav. const., =6.67408*10^(-11) m^3<span> kg^(</span>-1)<span> s^(</span>-2)
              M=mass of sun=1.989*10^(30) kg
=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}
=\frac{8.4826*10^44}{r^2}

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}
Solving for the real root:
r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}
=\frac{1.1681263*10^{35}}{\pi^2}
=2.279*10^11 m


5 0
3 years ago
In what way does the water cycle demonstrate the features of a cycle
anyanavicka [17]

Answer:

Step 1- Evaporation

Step 2- Condensation

Step 3- Sublimation

Step 4- Precipitation

Step 5- Transpiration

Step 6- Runoff

Step 7- Infiltration

Explanation:

6 0
3 years ago
John owns a debt of $500 to his landlord . His father had agreed to pay 3 over 5 of his amount for him . How much will his fathe
svlad2 [7]

Answer:

$300

Explanation:

60% of 500 is 300

3 over 5 is 60%

6 over 10 is 60%

5 0
3 years ago
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