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3 years ago

Which symbol is used to name a line with two points A and B

Mathematics

2 answers:

Phoenix [80]3 years ago

8 0

The symbol would be a simple line with 2 arrows at each end, above AB

Mars2501 [29]3 years ago

5 0

Answer:

Step-by-step explanation:

I think that's the answer

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ere is a picture of a cube and the net for this cube. What is the surface area of this cube? A. 1,350 mm2 B. 450 mm2 C. 225 mm2

lord [1]

Hello!

To find the surface area of a cube you do $6a^{2}$ where "a" is the length of one of the sides.

So $6 *15^{2}$ = 1350

the answer is 1350mm $^{2}$

Hope this helps!

8 0

3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

3 years ago

Please help me find y and show work/steps. I don't know how to do it

trasher [3.6K]

We will check if y and 60cm are parallel.

If the lengths 28cm, 56cm and 15cm, 30cm are in proportion, then y and the segment 60cm are parallel.

$\dfrac{56}{28}=\dfrac{30}{15}\\\\2=2\qquad CORRECT!$

OK. We know: y and 60cm are parallel. Therefore we have equation:

$\dfrac{y}{28+56}=\dfrac{60}{56}\\\\\dfrac{y}{84}=\dfrac{15}{14}\qquad|\text{cross multiply}\\\\14y=15\cdot84\qquad|\text{divide both sides by 14}\\\\y=90cm$

<h3>Answer: y = 90 cm.</h3>

5 0

3 years ago

Read 2 more answers

Rewrite csc theta/cot theta in terms of sine and cosine

STatiana [176]

Cot (theta) - csc (theta) = cos(theta) divided by sin(theta) - 1 divided by sin(theta) = cos(theta) - 1 divided by sin(theta) = the square root of 1-sin^2 (theta) -1 divided by sin(theta)

6 0

4 years ago

A scientist wants to find the radius, in meters, of this hemispherical dome. He found that the surface area of the entire sphere

Aneli [31]

Answer:

$r=\sqrt{\frac{682}{4\pi}}\ m$