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jek_recluse [69]
3 years ago
12

Solve 7+x/3 = 2x-5 Give all working out

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0
X = 36/5
Or x = 7.2


21 + x = 6x - 15
21 = 6x - 15 - x
21 = 5x - 15
21 + 15 = 5x
36 = 5x
36/5 = x
MariettaO [177]3 years ago
7 0
7+x/3 = 2x-5

multiply both sides by 3

21+x =6x-15

move the 6

21+x-6x = -15

move the 21

x-6x = -15-21

combine like terms

-5x = -15-21

divide both sides:

-5x = -36


answer: x = 36/5
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Lady_Fox [76]

Answer:

Part 1) y=32.5x+11.95

Par 2) see the explanation

Part 3) \$401.95

Step-by-step explanation:

Part 1) Write an equation in slope intercept form to represent this problem

Let

x ----> the number of tickets

y ---> the total cost

The linear equation in slope intercept form is equal to

y=mx+b    

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In this problem we have

b=\$11.95

ordered pairs (4,141.95) and (7,239.45)

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values in the formula

m=\frac{239.45-141.95}{7-4}

m=\frac{97.5}{3}

m=32.5

substitute the values in the linear equation

y=32.5x+11.95

Part 2) What does your slope represent in this problem? What does your y-intercept represent in this problem?

a) The slope of the linear equation represent the unit rate, so the slope represents the cost of one ticket

m=\$32.5\ per\ ticket

b) The y-intercept is the value of y when the value of x is equal to zero

In this context, the y-intercept represent the one-time  processing fee

b=\$11.95

Part 3) Use the equation to find how much Alan would have to pay for 12 tickets

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y=32.5(12)+11.95

y=\$401.95

3 0
4 years ago
You measure 2 cups of peanut butter into mixing bowl. How many 1/2 cups will you need?
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3 years ago
Taisha uses the elliptical cross- trainer at the gym. Her general goal is to burn 280 calories per workout, but she varies by as
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Given - Taisha has a general goal is to burn the 280 calories.

she is varies by the 25 calories.

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minimum calories equationbecomes

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The minmum calories burn by the taisha is 255 calories.

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