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Lubov Fominskaja [6]
3 years ago
12

Assume log bx = 0.49. Evaluate. Logbx^2

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0

Step-by-step explanation:

Use exponent property of logs.

logb(x²) = 2 logb(x) = 2(0.49) = 0.98

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faust18 [17]

Answer: mmm I don’t even understand what you trying to say but this doesn’t look like a question to me, is this even a question just saying

Step-by-step explanation:

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Given sin θ = 3/5 what is sec θ?
PIT_PIT [208]

Answer:

5/4

Step-by-step explanation:

To do this you must know that by definition secant is:


sec(\theta)=\frac{1}{cos(\theta)}


Furthermore:

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}


Based on this information we know that 3 = opposite and 5 = hypotenuse.  Assuming this is a right triangle we can determine the adjacent side by Pythagorean Theorem.

c^2=a^2+b^2

Where c is the hypotenuse, a is adjacent and b is opposite.  Therefore,

c^2=a^2+b^2\\\\a=\sqrt{c^2-b^2} \\\\a=\sqrt{5^2-3^2} \\\\a=4


And so the adjacent side of this triangle is 4.  Going back to the definition of secant we can now know that:

sec(\theta)=\frac{1}{cos(\theta)}=\frac{1}{\frac{4}{5}}=\frac{5}{4}

8 0
3 years ago
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X-3=10 does anyone know this
vovikov84 [41]

Answer:

Are you trying to solve for x?

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just kick the 3 to the other side, so a negative 3 would become a positive 3:

x= 10 + 3

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You can also use cymath it gives you the answer and explanation.

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Answer:

Step-by-step explanation:

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1. m∠QPR =<br><br> 2. m∠QTP =<br><br> 3. RP =<br> Show all the work
alex41 [277]

Answer:

1. 30°

2.90°

3. 12 units

Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

7 0
3 years ago
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