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3 years ago

Assume log bx = 0.49. Evaluate. Logbx^2

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

8 0

Step-by-step explanation:

Use exponent property of logs.

logb(x²) = 2 logb(x) = 2(0.49) = 0.98

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3 years ago

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide

ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{\sigma}{\sqrt{n}}$

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

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3 years ago

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11111nata11111 [884]

Answer:

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Step-by-step explanation:

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3 years ago

Multiply 3/7 by the reciprocal of -3/14

Alexandra [31]

Multiplying 3/7 by the reciprocal of -3/14,

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Hope it helps!!

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2 years ago

A certain bleach is 5% active ingredients. In 10 gallons of this bleach, how much is active ingredients? 0.05gallons 0.5gallons

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