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3 years ago

Really need helpppp?!

Mathematics

1 answer:

user100 [1]3 years ago

5 0

Answer:

6.43

pls follow me and mark brainliest ...thank u

Step-by-step explanation:

length of side x will be

Tan tita = opp/adjacent

tan65 = x/3

tan 65 is 2.14

so...you are left with 2.14=x/3

by cross multiplying

x= 2.14 × 3

= 6.43

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Please tell me the right answer.

Komok [63]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Okay I don't know this one either so uh help please

vodka [1.7K]

9514 1404 393

Answer:

(a) A'(-2, 1), B'(-4, -3), C'(-7, 0)

Step-by-step explanation:

If X is the center of rotation, the coordinates of point P are transformed like this:

P' = -(P -X) +X

P' = 2X -P

(x, y) ⇒ (2(-5) -x, 2(3) -y)

(x, y) ⇒ (-10-x, 6-y)

Your points are transformed to ...

A(-8, 5) ⇒ (-10-(-8), 6-5) = A'(-2, 1)

B(-6, 9) ⇒ (-10-(-6), 6-9) = B'(-4, -3)

C(-3, 6) ⇒ (-10-(-3), 6-6) = C'(-7, 0)

These coordinates match the first choice.

6 0

2 years ago

Which expressions are equivalent to -2y-8+4y

katrin2010 [14]

Answer:

2y-8

-Step-by-step explanation:

2y +4y = 2y

2y - 8

8 0

2 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

3 years ago

Please help me with this math homework thanks :)

Ivenika [448]

Place a point at (0,-5) because that is the y-intercept (the -5 on the vertical line)

Since the slope is negative two which can be re-written as -2/1 (rise/run) you go down two and to the right once or up two and to the left once, it doesn't matter which. Another point can be placed at (1,-7) or (-3,-1), it still doesn't matter which.

Then you can draw a line connecting the two points.

I hope this helps :)

Let me know if you need further explanation

3 0

2 years ago