The answer to this question would be: 40% or 0.4
In this question, you are asked the probability of hitting bull's eye on the fourth shot. This event is only one(only fourth, not all four shot) and should be independent to the first 3 shots. That mean, the chance should still 40% since every shot chance is 40%.
Let x be the number of child tickets he bought
Let y be the number of adult tickers he bought
① x+y=7 (child tickets+adult ticket=7 tickets in total)
② 2x+4y=24 (price of child tickets+price of adult tickets=$24 in total)
We may simply the second equation since all of the coefficients are divisible by 2.
① x+y=7
② x+2y=12
We can now use elimination by multiplying the second equation by -1.
② -(x+2y=12)
② -x-2y=-12
① x+y=7
② -x-2y=-12
Now putting the equations together,
-y=-5
y=5
x=2
Therefore he bought 2 child tickets and 5 adult tickets
She will have 6 braces left over since 8x8=64 and 70-64=6
Add -3 to -8 first. (Addition) because in PEMDAS, there is no parenthesis in this problem, no exponents, no multiplication, and no division. So addition is next.
If the [player runs between 4 bases and 90 each, you do 4*90, which is 360 feet. Since this is in yards, divide by 3. The answer is 120 yards.