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3 years ago

HELP ME PLS I DONT HAVE TIME

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

6 0

Answer:

A is true.......................b is false....................and c is false

Step-by-step explanation:

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There is a proportional relationship between your distance from a thunderstorm and the time from when you see the lightning and

eimsori [14]

Answer:

Yes.

Step-by-step explanation:

The relation would be 3 = k*9 as there is a direct proportional relationship.

So k = 3/9 = 1/3 and we can write the relation as d = 1/3 t where d=distance and t = time.

So if we double the time t we have:-

d = 1/3 * 18

= 6 kilometers.

So the distance is doubled.

3 0

3 years ago

For the vectors u and v with magnitudes u = 88 and v = 99, find the angle θ between u and v which makes u and v = 77.

WARRIOR [948]

Answer:

Step-by-step explanation:

Using the vector formula $u.v = |u||v|cos\theta$

|u| = magnitude of vector u

|v| = magnitude of vector v

u.v is the dot product of vector u and v

Given |u| = 88, |v| = 99 and u.v = 77, to get $\theta$ we will substitute the given values into the equation above;

$77 = 88*99cos\theta\\cos\theta = \frac{77}{88*99} \\cos\theta = \frac{77}{8712} \\cos\theta = 0.008838\\\theta = cos^{-1} 0.008838\\\theta = 89.5^{0}$

4 0

3 years ago

What is the cube root of 8x^27?<br> A) 2x^3<br> B) 2x^9<br> C) 4x^3<br> D) 4x^9

Tamiku [17]

Answer:

B) 2x^9

Step-by-step explanation:

i hope that helps

8 0

3 years ago

I need help please

devlian [24]

I am pretty sure its B (minimum at -1, -4) because that would be were the first point would be at. The Graphing of this equation would be a "upside down u" shape.

4 0

3 years ago

I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help

VMariaS [17]

Answer: a) 8.779 years

b) 8.664 years

<u>Step-by-step explanation:</u>

$A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

A: accumulated amount (balance)
P: principal amount (original/initial investment)
r: interest rate (convert to a decimal)
n: number of times compounded per year
t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

$1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}$

$A=Pe^{rt}$

$1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}$

4 0

2 years ago