mean = 4.2
mode = 2
median = 2.5
Least to greatest : mode (2), median (2.5), mean (4.2)
Answer:
0.6710
Step-by-step explanation:
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.
Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 107 mm
σ is the population standard deviation = 5 mm
For x = 104 mm
z = 104 - 107/5
z = -0.6
Probability value from Z-Table:
P(x = 104) = 0.27425
For x = 115 mm
z = 115 - 107/5
z = 1.6
Probability value from Z-Table:
P(x = 115) = 0.9452
The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:
P(x = 115) - P(x = 104)
0.9452 - 0.27425
= 0.67095
Approximately = 0.6710
It is always isosceles because it can be proved as follows:
The perpendicular bisector dissects the triangle into two, and it is the common side. Then each side of the bisector is 90 degrees, and the bisected to two equal sides, so the two dissected triangles are congruent, hence the original triangle is isosceles.
Answer:
The required solution is (5.75,-0.5). It can be written as 
.
Step-by-step explanation:
The given equations are
.... (1)
.... (2)
Multiply the equation (2) by 2.
.... (3)
Subtract equation (1) from equation (3).
Put this value in equation (1).
Therefore the required solution is (5.75,-0.5). It can be written as .
Answer: A. 0.20
Step-by-step explanation:
Let A be the event of employees needed corrective shoes and B be the event that they needed major dental work .
We are given that : 
We know that 
Then, 
Hence, the probability that an employee selected at random will need either corrective shoes or major dental work : 
hence, the correct option is (A).
