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Stolb23 [73]
3 years ago
9

Please HELP PAST DUE I NEED THE GRADE help!!!

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

(A:) I created a scatter plot similar to the one i used for mine, this is for the first part of your question

(B:) Positive Association

Step-by-step explanation:

(B:) Why? Because as your x value increases so does your y and it shows this with the data as well.

I had a tough time with this until i actually read through what it was really asking so i hope this helps you

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Find the common difference for the sequence shown 1/4,5/16,3/8
Vladimir79 [104]
<span>common difference for the sequence = 1/16

cause
1/4 = 4/16
and
3/8 = 6/16

so
4/16 + 1/16 = 5/16
5/16 + 1/16 = 6/16

</span>
4 0
3 years ago
The sound intensity of rustling leaves is 100 times the reference intensity. Use your graph to determine the sound intensity of
wariber [46]

The sound intensity of rustling leaves,  y = 20 decibels

<u>Step-by-step explanation:</u>

y = 10logx

The sound intensity of rustling leaves is 100 times the reference intensity.

x = ratio of intensity of sound to reference to intensity

x = 100:1 or x = 100

y = 10 log(100) = 10 * 2 = 20 decibels

y = 20 decibels

4 0
3 years ago
Read 2 more answers
Solve the following equation. log Subscript 2 Baseline (3 x plus 7 )equals 5 The solution set is StartSet nothing EndSet . ​(Sim
tigry1 [53]

Answer: x=\dfrac{25}{3}

Step-by-step explanation:

The given equation : \log_2(3x+7)=5

Using logarithmic property : \log_a N=M\to N=a^M

The given equation will be equivalent to (3x+7)=2^5

\Rightarrow\ 3x+7=32

Subtract 7 from both sides , we get

3x=25

Divide both sides by 3 , we get

x=\dfrac{25}{3}

Hence, the solution is x=\dfrac{25}{3}

3 0
3 years ago
Please subscribe to my friends channel <br> channel is called morrison pereira
neonofarm [45]

Answer:

ok

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
12. A flat, square roof needs a square patch in the corner to seal a leak. The side length of
NISA [10]

Answer:

Step-by-step explanation:

Area of the good part= area of whole roof - area of bad part

Since the roof is a square roof, the area will be calculated using the formulae for area of a square

Area of a square =length²

Area of good part =(x+12)²-x²

A= {(x+12)(x+12)} - x²

A = (x²+12x+12x+144) -x²

Open the bracket and rearrange the equation

A= x²-x²+24x+144

A=(24x+144) ft

5 0
3 years ago
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