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WINSTONCH [101]
3 years ago
13

What’s the answer????

Mathematics
2 answers:
butalik [34]3 years ago
7 0

Step-by-step explanation:

< this is the answer hope it helpsss

mr_godi [17]3 years ago
4 0

Answer:

The symbol is <

Step-by-step explanation:

1001 is less than 1010 so therefore

1001 is < than 1010 or

1001 < 1010

< is less than, > is greater than, = is equal to

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A store is having a 1/8 off sale. What percentage of each item sold does the cashier subtract to find the sale price
Sav [38]

Answer:

8 percent or .8

Step-by-step explanation:

Have a great day

3 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
You work in the HR department at a large franchise. you want to test whether you have set your employee monthly allowances corre
ra1l [238]

Answer:

1) Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

For this case we see that the calculated value is higher than the critical value

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

2) Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

Step-by-step explanation:

Part 1

Data given

\bar X=640 represent the sample mean

\sigma=150 represent the population standard deviation

n=40 sample size  

\mu_o =500 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Step1:State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 500, the system of hypothesis would be:  

Null hypothesis:\mu \leq 500  

Alternative hypothesis:\mu > 500  

Step 2: Calculate the statistic

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

z=\frac{640-500}{\frac{150}{\sqrt{40}}}=5.90  

Step 3: Calculate the critical value

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.01 of the area in the right and we got:

z_{crit}= 2.33

Step 4: Compare the statistic with the critical value

For this case we see that the calculated value is higher than the critical value

Step 5: Decision

Since the calculated value is higher than the critical value we have enugh evidence to reject the null hypothesis at 1% of significance level

Part 2

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>5.90)=1.82x10^{-9}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, same conclusion for part 1

7 0
3 years ago
What are the solutions to the equation x2 = 289?
artcher [175]
Because this is a second degree equation you will have 2 solutions.  When you take the square root of a number you have to account for both the positive and negative roots.  Since the square root of 289 is 17 then your solutions are +17 and -17.
3 0
4 years ago
Which inequality is NOT true when x= -2?
Levart [38]

Answer: D

Step-by-step explanation:

-7 isn't greater than -4

3 0
3 years ago
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