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Serggg [28]
4 years ago
6

i need help quick!! this is unit 1:geometry basics. homework 5: angle relationships if anyone know tell me

Mathematics
2 answers:
EleoNora [17]4 years ago
5 0

Answer:

I do not know the answer of 6 and 7

Hatshy [7]4 years ago
4 0

Am I correct?

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If the complex number x = 3 + bi and |x|^2 = 13, which is a possible value of b?
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If x=3+bi, then

|x|=\sqrt{3^2+b^2}.

You know that |x|^2=13, then

\left(\sqrt{3^2+b^2}\right)^2=13,\\ \\ 9+b^2=13,\\ \\b^2=4,\\ \\b=\pm 2.

Two possible complex numbers satisfy these conditions:

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<span>We know Sin theta is given by Perpendicular/ hypotenuse. Hence in this case the angle given is 30 degree and hypotenuse is given as 10 foot. Hence Sin 30= P/ 10 1/2= P/10 Hence on solving value of P is 5. Now we have to compute the theta value for Perpendicular as 5 and now the height of ramp is increased to 15 foot, hence hypotenuse is now 15 foot. Hence Sin theta= 5/15 On taking inverse of Sin Theta we will get the theta value as 19.47. Hence the angle of ramp should is 19.47 degrees.</span>
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