Answer:
The correct answer is:
(a) 0.54
(b) 0.0385
Step-by-step explanation:
Given:
Restaurant tax,
p = 0.54
Sample size,
n = 168
Now,
(a)
The mean will be:
⇒ μ ![\hat{p}= p](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%20p)
![=0.54](https://tex.z-dn.net/?f=%3D0.54)
(b)
The standard error will be:
= ![\sqrt{[\frac{p(1-p)}{n} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.54\times 0.46)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.54%5Ctimes%200.46%29%7D%7B168%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.2484)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.2484%29%7D%7B168%7D%20%5D%7D)
= ![0.0385](https://tex.z-dn.net/?f=0.0385)
Answer:
the area of the hexagon is 68 cm²
Step-by-step explanation:
Let us observe the image a little, we can find the area of the hexagon equals to the area of the large rectangle minus 4 small triangles surrounding the hexagon. The area of the rectangle is 8 × 12 is 96 cm². The area of 1 small triangle is 4 × 3.5 ÷ 2 = 7, there are 4 triangles, so the total area is 4 × 7 = 28. So the hexagon's area is 96 - 28 = 68 cm²
Hope this will help❤️
Answer:
sure?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
The average temperature is ![T_{a} = 81.95^oC](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%2081.95%5EoC)
Step-by-step explanation:
From the question we are told that
The temperature of the coffee after time t is ![T(t) = 25 + 72 e^{[-\frac{t}{45} ]}](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%2025%20%2B%2072%20e%5E%7B%5B-%5Cfrac%7Bt%7D%7B45%7D%20%5D%7D)
Now the average temperature during the first 22 minutes i.e fro
minutes is mathematically evaluated as
![T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%20%20%5Cfrac%7B1%7D%7B22-0%7D%20%20%5Cint%5Climits%5E%7B22%7D_%7B0%7D%20%7B25%20%2B72%20e%5E%7B%5B-%5Cfrac%7Bt%7D%7B45%7D%20%5D%7D%7D%20%5C%2C%20dx)
![T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%20%5Cfrac%7B1%7D%7B22%7D%20%5B25%20t%20%20%2B%20%2072%20%5B%5Cfrac%7Be%5E%7B%5B-%5Cfrac%7Bt%7D%7B45%7D%20%5D%7D%7D%7B-%5Cfrac%7B1%7D%7B45%7D%20%7D%20%5D%20%5D%20%5Cleft%7C%2022%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
![T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%20%5Cfrac%7B1%7D%7B22%7D%20%5B25%20t%20%20-%203240e%5E%7B%5B-%5Cfrac%7Bt%7D%7B45%7D%20%5D%7D%20%5D%20%5Cleft%20%7C%2045%7D%20%5Catop%20%7B%7B0%7D%7D%20%5Cright.)
![T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%20%5Cfrac%7B1%7D%7B22%7D%20%5B25%20%2822%29%20%20-%203240e%5E%7B%5B-%5Cfrac%7B22%7D%7B45%7D%20%5D%7D%20%20%20-%20%28-%203240e%5E%7B0%7D%20%29%5D)
![T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%20%5Cfrac%7B1%7D%7B22%7D%20%5B550%20%20-%201987.12%20%20%2B%20%203240%5D)
![T_{a} = 81.95^oC](https://tex.z-dn.net/?f=T_%7Ba%7D%20%3D%2081.95%5EoC)