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AleksandrR [38]
3 years ago
6

The width of a rectangle is 2 units less than the length. The area of the rectangle is 63 units. What is the length, in units, o

f the rectangle?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer: Length = 9 units

Step-by-step explanation:

Let L represent the length of the rectangle.

The width of a rectangle is 2 units less than the length. It means that the width of the rectangle is (L - 2) units.

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of the rectangle is 63 units. It means that

L(L - 2) = 63

L² - 2L = 63

L² - 2L - 63 = 0

L² + 7L - 9L - 63 = 0

L(L + 7) - 9(L + 7) = 0

L - 9 = 0 or L + 7 = 0

L = 9 or L = - 7

Since the length cannot be negative, then

L = 9 units

Width = 9 - 2 = 7 units

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4 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
leonid [27]

Answer:

\boxed {\boxed {\sf d\approx 4.2}}

Step-by-step explanation:

The formula for distance is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Where (x₁, y) and (x₂, y₂) are the points.

We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:

  • x₁= -6
  • y₁ = 6
  • x₂ = -3
  • y₂ = 3

Substitute the values into the formula.

d= \sqrt{ (-3 - -6)^2+(3-6)^2

Solve inside the parentheses.

  • -3 --6 = -3+6 = 3
  • 3-6 = -3

d= \sqrt{(3)^2+ (-3)^2

Solve the exponents.

  • (3)²= 3*3= 9
  • (-3)²= -3*-3 =9

d= \sqrt{9+9

Add.

d= \sqrt18

d= 4.24264069

Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.

d \approx 4.2

The distance between the two points is apprximately <u>4.2</u>

4 0
3 years ago
If 3x - 2 = -x + 10, then x =
Kipish [7]

Answer:

3

Step-by-step explanation:

3x-2= -x+10

4x= 12

x=3

5 0
3 years ago
Read 2 more answers
PLZ HELP WILL GIVE BRAINLIEST
Naddik [55]

y  = -0.65 (6) + 7.34

y = 3.44

but the dot plot showed when x = 6, y = 4

so 4 - 3.44 = 0.56

Answer

0.56



3 0
3 years ago
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