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marin [14]
3 years ago
14

Question three!!!!!!!!

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0
The answer is b 15 hope this helps
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The competitive advantage of small American factories such as Tolerance Contract Manufacturing lies in their ability to produce
Tom [10]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

H_0: \sigma^{2} \leq 0.0008\\\\H_a:  \sigma^{2} > 0.0008

The testing states value is:

\to x^2=\frac{(n-1)s^2}{\sigma^2}=32.6250

therefor the \rho - \ value = 0.2931

Through out the above equation its values Doesn't rejects the H_0 value, and its  sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.

5 0
3 years ago
An equation is shown 120÷ __ =1.20
devlian [24]

an equation is shown 120÷ __ =1.20

120 / x = 1.2

120/100 = 1.2

check:

1.2* 100 = 120

3 0
3 years ago
Read 2 more answers
In the figure below, m∠1 = x and m∠2 = x - 4. Which statement could be used to prove that x = 47?
dangina [55]

The answer is C) m∠1 + m∠2 = 90

Explanation: So ∠1 is x and ∠2 is x-4

Basically you know than ∠3 is 90° ... And a straight line is 180° ..                            So technically we can just find out 180-90 is 90(the other angle 1 + 2).

To get 90° we'll add ∠1 and ∠2 in other ways, like technical thinking-

So you already know adding ∠1 and ∠2 is 90°. So ∠1 + ∠2 = 90°

In other words you can say m∠1 + m∠2 = 90

3 0
3 years ago
How do you solve this problem? (x+3) cubed
Lubov Fominskaja [6]
You would expand becausee it isn't equal to anything

(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one

so
for the 3rd power
(a+b)^3=1a^3+3a^2b^1+3a^1b^2+1b^3

a=x
b=3

(x+3)^3=1x^3+3x^2(3^1)+3x^1(3)^2+1(3)^3=
x^3+9x^2+27x+27


7 0
4 years ago
Read 2 more answers
PLEASE HELP ITS URGENT!!<br> Given: △ABC is isosceles; 1 ≅ 3<br> Prove: AB || CD
Dmitrij [34]

Answer:

AB ║ CD. (Proved)

Step-by-step explanation:

See the attached diagram of the triangle.

It is given that Δ ACD is an isosceles triangle.

Therefore, AC = AD and ∠ ACD = ∠ ADC, ⇒ ∠ 3 = ∠ 4 .......... (1)

Again, given that ∠ 1 = ∠ 3 ........... (2)

Now, from equations (1) and (2) we can write, ∠ 1 = ∠ 4

Now, AB and CD are two straight lines and AD is the transverse line and hence, ∠ 1 and ∠ 4 are alternate angles that are equal.

Therefore, AB and CD are parallel straight lines and AB ║ CD. (Proved)

4 0
4 years ago
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