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Natasha_Volkova [10]
3 years ago
6

Identify as a direct variation, inverse variation or neither. y = 6x

Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

y=6x is a direct variation.

Step-by-step explanation:

In direct variation the relation between two variable is direct. It means y varies directly as x.

y\propto x

y=kx

Where, k is constant of proportionality.

In inverse variation the relation between two variable is inversely proportional. It means y varies inversely as x.

y\propto \frac{1}{x}

y=k \frac{1}{x}

Where, k is constant of proportionality.

The given function is

y=6x

It is direct variation because y varies directly as x and constant of proportionality is 6.

Therefore, y=6x is a direct variation.

Naddika [18.5K]3 years ago
5 0
This Is Direct Variation Because Y Always Varies Directly With X. It
Is Always 6 Times As Large As X.
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PLEASE HELP DUE IN TONIGHT!!!
wel

Answer:

(1,2)

Step-by-step explanation:

4×1=4

3×2=6

then add 4+6 to get 10

then you do the same for the bottom so

5×1=5

4×2=8

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4 0
3 years ago
Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

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Answer:

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Step-by-step explanation:

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Pair 2 would be a translation.

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