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2 years ago

14

Convert. 23 ft = yd ft

2 answers:

liq [111]2 years ago

8 0

Answer:

7 yards converted {}

mihalych1998 [28]2 years ago

8 0

Answer:

Step-by-step explanation:

23 ft = 7.66667 yd's

You divide 23 by 3 and you will get a decimal of 7.6 continued 6 5 times eventually leading to a 7.

Answered by NONE other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO!!!

HOPE THIS HELPED!!!

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What is the volume of a square pyramids

frozen [14]

Answer:

$\large\boxed{V=75\ in^3}$

Step-by-step explanation:

The formula ogf a volume of a pyramid:

$V=\dfrac{1}{3}BH$

B - area of a base

H - height

We have a base length a = 5 in and a height H = 9 in.

In the base we have a square. The formula of an area of a square is:

$B=a^2$

Substitute:

$B=5^2=25\ in^2$

Calculate the volume:

$V=\dfrac{1}{3}(25)(9)=(25)(3)=75\ in^3$

7 0

3 years ago

I have more yeyeyey

frozen [14]

Answer:

<h3>y≤9</h3>

Step-by-step explanation:

8 0

2 years ago

The sum of the roots of 3x 2 + 11x - 4 = 0 is<br><br> -11/3<br> -4/3<br> 11/3<br> 4/3

givi [52]

Answer:

The correct option is 1.

Step-by-step explanation:

If a quadratic equation is defined as

$ax^2+bx+c=0$ .... (1)

Then the sum of the roots is -b/a and the product of roots is c/a.

The given equation is

$3x^2+11x-4=0$ ... (2)

From (1) and (2) we get a=3, b=11 and c=-4.

The sum of roots is

$\frac{-b}{a}=-\frac{11}{3}$

The sum of roots is $-\frac{11}{3}$ .

Therefore the correct option is 1.

5 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

What is the first step in solving 5v+9=−51

diamong [38]

Answer:

subtract 9 then when u get the answer divide by 5

Step-by-step explanation:

6 0

3 years ago