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Akimi4 [234]
3 years ago
12

Why does putting a lid over red cabbage help it keeps it color

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

It is blocking out some bacteria that feast on the cabbage.making it lose it's color.

Step-by-step explanation:


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A library has 9,000 books. During renovations, the library wants to pack them into boxes that hold 10 books each. How many boxes
yawa3891 [41]

Answer: 900 boxes

Step-by-step explanation: When you take 9,000 and divide it by the number of books in a box(10) you get 900

3 0
3 years ago
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!!!!Pls help!!!!!
hichkok12 [17]

Answer:

(2,4) is a solution to this system of equations

Step-by-step explanation:

Given system of equation are

y=2x \hfill (1)

y=\frac{-1}{2}x+5\hfill (2)

To find the solution of the given system of equations

To Check that (2,4) is a solution to this system or not

Solving equations (1) and (2)

From equation (1) and y=2x

Now substitute y=2x is equation (2)

2x=\frac{-1}{2}x+5

\frac{-1}{5}x+5-2x=0

5-\frac{x}{2}-2x=0

5-\frac{x+4x}{2}=0

5-\frac{5x}{2}=0

\frac{10-5x}{2}=0

10-5x=0

-5x=-10

x=\frac{10}{5}

Substitute x=2 in equation (1)

y=2x

y=2(2)

Therefore y=4

Therefore the solution is (2,4)

Therefore (2,4) is a solution to the system of equations.

4 0
3 years ago
The area of the circle is square
Igoryamba

Answer:

16л, 8л

Step-by-step explanation:

r=4

area=4*4л

=16л

circumference= 2л*4

=8л

4 0
2 years ago
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What is 12.1 repeating as a fraction in simplest form?
dem82 [27]
The answer is two, one over nine⬇️
2\ \frac{1}{9}
8 0
3 years ago
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A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st
shutvik [7]

Answer:

Equation of movement y(t)

y(t)=sin(10t-\pi/2)

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

A=1\,inch

The period depends on the mass and the spring constant.

The formula for the period is:

T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s

The model y(t) for the movement of the mass-spring system is

y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)

8 0
3 years ago
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