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2 years ago

Please help me with this problem!

Mathematics

1 answer:

mina [271]2 years ago

4 0

Answer:

Step-by-step explanation:

The diagram shows lines passing through the points of two equations.

We will determine the points through which the lines pass through on the graphs.

Looking at the line on the right hand side of the graph, the slope is

(y2-y1)/x(2-x1) where

y2= 0, y1 = 4

x2 = 3, x1=0

Slope, m = (0-4)/3-0

Slope = -4/3

Recall the equation of a straight line is y = mx + c

Where c is the intercept.

So the equation is y

y = -4x/3 + 4

Looking at the line on the left hand side of the graph, the slope is

(y2-y1)/x(2-x1) where

y2= 0, y1 = 2

x2 = -1, x1 =0

Slope, m = (0-2)/-1-0

Slope = -2/-1 = 2

Applying equation of a straight line is y = mx + c

The equation

y = 2x + 2

So the equations are

-4x/3 + 4. If x lesser than or equal 0

2x + 2. If x greater than 0

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Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

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For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

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$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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